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solve question 16 with complete explanation within 15-30 mins and get multiple upvotes
30. Assuming that electrons enter the following parallel plate with a horizontal velocity of 3.20 x 106 m/ s, how far will the electrons travel horizontally before they crash into the positive plate? [5.58 x 10² m] 31. A proton is placed in an electric field between two parallel plates. If the plates are 6.0 cm apart and have a potential difference between them of 7.5 x 101 v, how much work is done against the electric field when the proton is moved 3.0 cm parallel to the plates? [0] 32. In the previous question, how much work would be done against the electric field if the proton was moved 3.0 cm perpendicular to the plates? [6.0 x 10-18 J] 16. A charge of -5.00 C is separated from another charge of -2.00 C by a distance of 1.20 m. Calculate a) The net electric field midway between the two charges [7.49 x 1010 N/C [toward the -5.00 C charge]] b) The position where the net electric field is zero. [0.735 m from the -5.00 C charge]
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Transcribed Image Text:30. Assuming that electrons enter the following parallel plate with a horizontal velocity of 3.20 x 106 m/ s, how far will the electrons travel horizontally before they crash into the positive plate? [5.58 x 10² m] 31. A proton is placed in an electric field between two parallel plates. If the plates are 6.0 cm apart and have a potential difference between them of 7.5 x 101 v, how much work is done against the electric field when the proton is moved 3.0 cm parallel to the plates? [0] 32. In the previous question, how much work would be done against the electric field if the proton was moved 3.0 cm perpendicular to the plates? [6.0 x 10-18 J] 16. A charge of -5.00 C is separated from another charge of -2.00 C by a distance of 1.20 m. Calculate a) The net electric field midway between the two charges [7.49 x 1010 N/C [toward the -5.00 C charge]] b) The position where the net electric field is zero. [0.735 m from the -5.00 C charge]
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