Answer A4, B1, and B2:A. Assume this as your target population. Suppose this data constitute a normal distribution.156182154146160156160139162137158145155157150152165149150171162144141156148165157167154169167162166163154129166153164156152160160155162167147160168142135145146150169156186155158156144160148175153157152150158157151165163159173145162157150152144138168158159141161160151163161168164165164139161136173163 Find the mean height and the population standard deviation.By simple random sampling, obtain a sample of 10 students. Compute the sample mean. Obtain the 90% confidence interval (CI) of the population mean using this sample.From the sample you obtain in (b), compute the 95% confidence interval of the population mean. What do you observe about the width of 90% CI compared 95% CI. Make a general statement on the margin error as confidence level increases.By simple random sampling, obtain a sample of 20 students. Compute the sample mean. Obtain the 95% CI of the population mean. What do you observe about the width of 95% CI from 20 samples compared to the width of 95% CI from 10 samples. Make a general statement on the margin of error as the sample size increases.B. Refer to the data about the height 100 senior high school student. Assume this as your target population. Suppose this data constitute a normal distribution.By simple random sampling, obtain a sample of 5 students. Compute the sample mean. Obtain the 90% CI of the population mean using this sample. Repeat this process 20 times. At the end, you will have a list of 20 90%-confidence interval with sample size equal to 5.From 2a, count how many intervals contain the population mean. Is the percent of confidence intervals that contain the population mean μ close to 90%?

Name: Answer A4, B1, and B2:A. Assume this as your target population. Suppos
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: Answer A4, B1, and B2:A. Assume this as your target population. Suppose this data constitute a normal distribution.156182154146160156160139162137158145155157150152165149150171162144141156148165157167154169167162166163154129166153164156152160160155162

1) mean height = ∑xn = 15644100 = 156.44 population standard deviation = ∑(xi-x)2n = 10230.64100 =…

Answered: 156 148 165 157 167 154 169 167…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Topic Video

Question

Answer A4, B1, and B2:

A. Assume this as your target population. Suppose this data constitute a normal distribution.

156	182	154	146	160	156	160	139	162	137
158	145	155	157	150	152	165	149	150	171
162	144	141	156	148	165	157	167	154	169
167	162	166	163	154	129	166	153	164	156
152	160	160	155	162	167	147	160	168	142
135	145	146	150	169	156	186	155	158	156
144	160	148	175	153	157	152	150	158	157
151	165	163	159	173	145	162	157	150	152
144	138	168	158	159	141	161	160	151	163
161	168	164	165	164	139	161	136	173	163

Find the mean height and the population standard deviation.
By simple random sampling, obtain a sample of 10 students. Compute the sample mean. Obtain the 90% confidence interval (CI) of the population mean using this sample.
From the sample you obtain in (b), compute the 95% confidence interval of the population mean. What do you observe about the width of 90% CI compared 95% CI. Make a general statement on the margin error as confidence level increases.
By simple random sampling, obtain a sample of 20 students. Compute the sample mean. Obtain the 95% CI of the population mean. What do you observe about the width of 95% CI from 20 samples compared to the width of 95% CI from 10 samples. Make a general statement on the margin of error as the sample size increases.

B. Refer to the data about the height 100 senior high school student. Assume this as your target population. Suppose this data constitute a normal distribution.

By simple random sampling, obtain a sample of 5 students. Compute the sample mean. Obtain the 90% CI of the population mean using this sample. Repeat this process 20 times. At the end, you will have a list of 20 90%-confidence interval with sample size equal to 5.
From 2a, count how many intervals contain the population mean. Is the percent of confidence intervals that contain the population mean μ close to 90%?

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Hypothesis Tests and Confidence Intervals for Means$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.

156	182	154	146	160	156	160	139	162	137
158	145	155	157	150	152	165	149	150	171
162	144	141	156	148	165	157	167	154	169
167	162	166	163	154	129	166	153	164	156
152	160	160	155	162	167	147	160	168	142
135	145	146	150	169	156	186	155	158	156
144	160	148	175	153	157	152	150	158	157
151	165	163	159	173	145	162	157	150	152
144	138	168	158	159	141	161	160	151	163
161	168	164	165	164	139	161	136	173	163

156	182	154	146	160	156	160	139	162	137
158	145	155	157	150	152	165	149	150	171
162	144	141	156	148	165	157	167	154	169
167	162	166	163	154	129	166	153	164	156
152	160	160	155	162	167	147	160	168	142
135	145	146	150	169	156	186	155	158	156
144	160	148	175	153	157	152	150	158	157
151	165	163	159	173	145	162	157	150	152
144	138	168	158	159	141	161	160	151	163
161	168	164	165	164	139	161	136	173	163

156 148 165 157 167 154 169 167 162 166 163 154 129 166 153 164 156 152 160 160 155 162 167 147 160 168 142 135 145 146 150 169 156 186 155 158 156 144 160 148 175 153 157 152 150 158 157 151 165 163 159 173 145 162 15

156	182	154	146	160	156	160	139	162	137
158	145	155	157	150	152	165	149	150	171
162	144	141	156	148	165	157	167	154	169
167	162	166	163	154	129	166	153	164	156
152	160	160	155	162	167	147	160	168	142
135	145	146	150	169	156	186	155	158	156
144	160	148	175	153	157	152	150	158	157
151	165	163	159	173	145	162	157	150	152
144	138	168	158	159	141	161	160	151	163
161	168	164	165	164	139	161	136	173	163