3 z.10245° N, are connected to an abc-3. Threewye-connectedloadimpedances,= 15260° N,z,204-30Ω, and z.sequence, balanced 3-phase, wye-connected source with a line voltage of 208V. The line impedance per phase is 4 + j202. Two wattmeters are used tomeasure the total real power drawn by the load. Show the wattmeterconnections. Calculate the wattmeter readings and the total load power.

In this solution the concept related to the two wattmeter method is discussed.

= 15260' 2, z, = 202 - 30° n, and z, = 1045 2, are connected to an abc- 3. Three wye-connected load impedances, z. sequence, balanced 3-phase, wye-connected source with a line voltage of 208 V. The line impedance per phase is 4 + j200. Two wattmeters are used to measure the total real power drawn by the load. Show the wattmeter connections. Calculate the wattmeter readings and the total load power.

= 15260' 2, z, = 202 - 30° n, and z, = 1045 2, are connected to an abc- 3. Three wye-connected load impedances, z. sequence, balanced 3-phase, wye-connected source with a line voltage of 208 V. The line impedance per phase is 4 + j200. Two wattmeters are used to measure the total real power drawn by the load. Show the wattmeter connections. Calculate the wattmeter readings and the total load power.

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter2: Fundamentals

Section: Chapter Questions

Problem 2.24MCQ: Consider a three-phase Y-connected source feeding a balanced- load. The phasor sum of the line...

See similar textbooks

Similar questions

A star connected three phase alternator supplies power to a delta connected resistive load. The alternator has a line voltage of 480V. Each resistor of delta load has 8 ohm of resistance. Find the following values. Line voltage of the load (VL(load)) Phase voltage of the load (VP(load)) Phase current of the load (IP(load)) Line current delivered by the alternator (IL(alt)) Phase current of the alternator (IP(Alt)) Phase voltage of the alternator (VP(Alt)) True power
Two delta connected loads are connected in parallel and powered by a balanced Y-connectedsource. The smaller of two loads draws 10 kVA at a lagging power factor of 0.75 and the largerdraws 25 kVA at a leading power factor of 0.8. The line voltage is 400 V. Calculate a) The powerfactor at which the source is operating. b) The total power drawn by the two loads. c) The phasecurrent of each load.
Draw a 3-phase wye-connected generator with transmission lines connected to a 3-phase delta-connected load. Assume the lines connecting them have an inductance of j5 per phase. The generated voltages are 120 Vrms with phase 'a' having a phase angle of 0°. The loads are 10 Ohm resistors per phase. When drawing, make sure to label all 3 phases with voltage phasors, line inductances, and load resistances.
In a balanced delta connected 3-phase circuit, has resistance 25 ohm and inductive reactance 40 ohm, connected to a 400V,50HZ 3-phase supply voltage, then total power delivered to load is Select one: a. 5397.76W b. 1635.34KW c. 7593.26W d. NONE OF THESE
Draw Wye- Delta three phase transformers connection ( no-load and full-load) in Lt-spice
In the circuit in the figure; L1 load draws 15 kVA with lagging power factor 0.6. The L2 load draws 6 kVA with a leading power factor of 0.8. According to this; What is the value of the complex power for the L2 load?
A three-phase circuit is balanced. The source voltage for the a-phase has a magnitude of 100 volts, and you can assume the phase angle is a reference of 0 degrees. Write the phasor expressions with proper subscript notation for the source voltage for each leg of the three-phase source if it is in a positive phase sequence.
1. The following are the given for the circuit below: VRY = 220 cis 0°, VYB = 220 cis -120° and VBR = 220 cis -240°. IR = 10 cis 0°. The load is balanced and delta connected. Determine the: (a) Impedance per phase (b) Current per phase (c) Line currents. B R reellle relllle momm Y RY Iy IB ĪR B R ZBR VYB ZRY
A three-phase alternator generating unbalanced voltages is connected to an unbalanced load through a 3-phase transmission line as shown in figure. The neutral of the alternator and the star point of the load are solidly grounded. The phase voltages of the alternator are Ea = 1020º, Eb = 102-90°, Ec = 10/120⁰ E E E The positive sequence component of the load current is (A) 1.3102-107⁰ A (B) 0.3322-120° A (C) 0.9962-120º A (D) 3.5104-81⁰ A +) + j1.002 0000 j1.002 0000 j1.0Ω vovo j1.0Ω 0000 j2.002 voor j3.002 oooo
Given: 1. 2 wye-connected loads per phase to a 3 phase power source 2. first load consists of a 55ohm resistance and a 0.05H inductance per phase 3. second load consumes 1kW and power factor of 0.7 lagging per phase 4. RMS of voltage across the loads are 220V, frequency 120Hz per phase 5. single phase equivalent is shown in the figure: Question: What are the real, reactive, and apparent powers seen at load 1? Give also the power factor.
A voltage of 200 253"8' is applied across to impedances in parallel. The values of impedances are (12+j16j) and (10-j20). Determine the KVA, KVAR, and KW in each branch and the power factor of the whole circuit.
Three unequal, single phase inductive loads are connected between the lines 1-2, 2-3 and 3-1 of a 3 phase system. The line potentials are each 230V with V12 leading V23. The first load takes 100A at 0.707 pf, the second takes 150A at 0.8 pf and the third takes 28.4KW at 0.5 power factor. What will be the value of the two wattmeter connected for the two wattmeters method in measuring power if the current coils were in lines a and 2?