150.000 kN 180° F3 DEFAULT FO DEFAULT DEFAULT 100.000 kN 200.000 kN F6 DEFAULT F2 15 F7 DEFAULT 150.0 DEFAULT 83.333 kN 216.667 kN F5 DEFAULT F4 DEFAULT F8 DEFAULT

Q: Three lines have the following north azimuths: AB 114o36’, CD 254o45’, and EF 302o14’. What are the…

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Q: Using Area Moment Method (AMM), with R4= 110 k (upward) and MA= 580 k-ft (counter-clockwise),…

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Q: Determine the reactions of each structure

A: Given:- A structure is given with two-point loads  The magnitude of the point load at F = 8 kips The…

Q: Situation 1 Determine El6 at point B and end of the overhang. Round off your final answer In 2…

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Q: Compute adjusted forward bearings of the following open traverse;

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Q: Given the following differential level notes: STA ELEVATION BS HI FS 1.73 346.50m BM-A TP 1 i.85…

A: Given height of instrument method HI = elevation + BS elevation = HI - FS given elevation of BM a =…

Q: Determine which quadrant the angle terminates given the conditions: sec0 > 0 and tan0 < 0.

A: To find :- quadrant the angle terminates given the conditions: sec0 &gt; 0 (positive) and tan0 &lt;…

Q: Use K = 1.0 and E = 29,000 ksi, Fy = 50 ksi. No need to check the local stability of the column.…

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Q: 30 k 2 k/ft D C 6 ft- -10 ft FIG. P5.35

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Q: LINE BEARING Determine the following: 1-2 S 73° 21' E (a) Interior Angle 2-3 S 40° 10' E (b)…

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Q: 1. Find the orthogonal trajectory of the following: a. x² + 4y² = C Ans. y = Cx4 Ans. y² + 2lncosx +…

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Q: Q1/ Determine the resulting displacement of pin B. Assume: A1=A2= 900 mm2 , E1=E2= 100 GPa , a1=a2=…

A: Given Data: The area of member 1 and 2 is, A1=A2=900 mm2 The elastic modulus of member 1 and 2 is,…

Q: E = 29,000 ksi I = 4,000 in.+ Do FIG. P6.16, P6.42 64 k B -9 ft- -18 ft- -9 ft El = constant E =…

A: VA+VD=64VD36=649VD=16VA=4843227=x18x=288 draw the M/EI diagram  to find slope at C then find area…

Q: Given the ff. deflection angles of a closed traverse. Assume bearing of line AB is S 40° E. Station…

A: Angle Deflection Angle A 85⁰20' B 10⁰11' C 83⁰32' D 63⁰27' E 34⁰18' F 72⁰56' G 30⁰45'

Q: 20 kN/m 30 kN/m 10 m 5 m 10 m FIG. P5.61

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Q: SITUATION 2: A simply supported prismatic beam is loaded as shown. El = 1 000 000 kN.m² 1000 kN 500…

A: Given data: EI= 1000000 KN/m2

Q: Which of the following is the equation of slope at segment AB? P kN/m A C L O…

A: The length of beam =L+L2=3L2The left end support is pinned supportThe right end support is roller…

Q: ACTION- PROJECT PROBLEM 75 ft The ball is thrown off the top of the building. If it strikes the…

A: Given, XA=0XB=60 ftt= 3 secYA=0YB=-75 ft

Q: 2-7 Resolve the position vector A of the car (measured from fixed point O) into components parallel…

A: Introduction- A vector is a quantity that has both a direction and a magnitude, whereas a scalar…

Q: HA) 120KN Find slope and B deflection at B 3m 2m (B) W KN/m Find slope and deflection at B (C) 10…

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Q: We15 KN/m P-30

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Q: th horizontal velocity v4, determine

A: Velocity at point 'A' = 8ft/s Acceleration due to gravity (g) = 32.2 ft/square second. e= 0.8 Height…

Q: An open channel is to be designed to carry 1.5 m3/s at a slope of 0.007. The channel material has an…

A: solution  Given discharge Q = 1.5m3/secslope S =0.007n=0.012 for the most efficient rectangular…

Q: Building's basement elevation is 379.1 m. The stub-out connection elevation is 370.8 m „lf the…

A: Given that:                      Elevation of basement elevation=379.1 mElevation of Stub-out =…

Q: e beam loaded as shown and the Equations of the SPa, 1= 75 x 10 mm 2 kN/m 1.8 m B 3m →→x1 M(x) =…

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Q: 1. Solve for the elevation at BM2 Station BS FS Elevation BM1 5.87 392.25m TP1 7.03 6.29 TP2 3.48…

A: Calculate elevation of BM2?

Q: Use the conjugate-beam method to determine the slopes and deflections at points B and D of the beams…

A: A Conjugate beam is the imaginary beam with the same dimensions as that of the original beam but…

Q: eir 1.5m high is located in a 5m wide rectangular channel v velocity of approach.

A: WE KNOW THE FORMULA Q=1.84(L)(H+ha32-ha32)ha=va22gva=QB(H+Z)Z=Weir height H=Height upstream…

Q: Width U/S of dam = 49.3 , length of spillway = 23.8 , head above crest = 5.5 if approach velocity…

A: Solution: Given: Width of the dam (W)=49.3 Length of Spillway (Ls)=23.8 Height above crest (Hc)=5.5

Q: Given: D₁ = 10°30'; D₂ = 10°; 1₁ = 15°; 1₂ = 16°; STA V = 00 + 876 STATION CENTRAL ANGLE PC-1 PC-PCC…

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Q: BEARING OF PC-V = N 60° E BEARING OF V-PT S 70° E DEGREE OF CURVE CO) STATION Ve 12 t 234.50 %3D

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Q: 30 kN 20 kN B. D F 1.5 m 2 m |C E G -2 m -2 m- -2 m- Fig. P6.53 and P6.54

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Q: Use E... b Draw the longitudinal section ( profile) of the leveling process if vou know that the…

A: Longitudinal profile is constructed to understand elevation as well as horizontal distance between…

Q: Q=455 N E B 2m P= 320 N D с 2 m

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Q: F3 150.000 kN, 180° DEFAULT F8 DEFAULT F5 DEFAULT FO DEFAULT 200.000 kN 100.000 kN 150.0 F7 DEFAULT…

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Q: R1=8.666 & R2=11.334??

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Q: Width U/S of dam = 48.7 , length of spillway = 9.2, head above crest = 10.3 if approach velocity…

A: Head above crest (Hac) = 10.3 m  length of spillway (L) = 9.2 m  width of u/s of dam (w) = 48.7 m

Q: GIVEN: G1 = 3 % ELEV V = 71.50 L = 800 m G2 = - 2% STA V = 10 + 00 Determine elevations at…

A: Grade of backward tangent, g1 =3%Grade of forward tangent, g2 =-2%The Length of vertical parabolic…

Q: Given: D₁ = 10°30'; D₂ = 10°; I₁ = 15°; 1₂ = 16°; STA V = 00 + 876 STATION CENTRAL ANGLE PC-1 PC-PCC…

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Q: Water flows in a trapezoidal channel with side slope 1V:3H, bottom width of 16ft and water depth of…

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Q: Q2- Compute the factor of safety for Slope Number 2 using Janbu’s o = 0 charts (y = 15.77 kN/m³). Su…

A: From the given Data

Q: 1. Draw the profile of the following vertical alignment: Grade -1.5% Line Length 195.6 m 197.43 m L1…

A: Calculate the algebraic change in slope direction and tabulate them A1 -1.5-3.0 4.5 A2 3.0--2.0…

Q: F3 150.000 kN, 180 DEFAULT F8 DEFAULT F5 DEFAULT FO DEFAULT 200.000 kN 100.000 kN F7 150.0 F2…

A: we can solve this question by using joint analysis

Q: Determine the A6z = at a point 3.00 meters from the inclined Iineload and 2.5 meters deep. µ = 0.35…

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Q: At the instant shown, the slider D has a velocity of 3 ft/s up the channel and its speed is…

A: Given : The slider D has a velocity - 3 ft/s Decreasing speed at a rate of 0.5 ft/s2 To Find :

Q: Reverse Curve Given First PI- 33 + 50. 15 75 20 00 L deFlection cngle Pl2 -40 + 16.70 83° 50'00"R…

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Q: Given: FB = (400î – 400j- 200k) Find: (a) Fc = ? (b) FR = FB + F and a = ? (c) Angle be tween Fg and…

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Q: Water flows in a trapezoidal channel with side slope 1V:3H, bottom width of 16ft and water depth of…

A: Area of the…

Q: 11. When So > 0 and Yn < Yc, it is called as a) Adverse b) Horizontal c) Critical d) Steep

A: Channel slope  classification can be done based on slope S and normal depth yn and critical depth…

Q: 4.6 An open traverse that runs from A through H has the following deflection angles: 8-6°25'R, C=…

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