150° 9 270° -2q Q What is the electric field at the center of the circle due to these point charges? (Express your answer in vector form. Use the following as necessary: ker 9, and r.) E = 3k q ,.2 -j (b) What If? What is the minimum electric field magnitude that could be obtained at the center of the circle by moving one or more of the charges along the circle, with a minimum separation of 3.90° between each of the charges? Express your result as the ratio of this new electric field magnitude to the magnitude of the electric field found in part (a). Eminimum 0.0015 Epart (a) Place the two charges +q at 0 = 270° ±y, where y is the smallest angle at which the charges do not overlap with the charge -2q, then write an expression for the electric field at the center.

150° 9 270° -2q Q What is the electric field at the center of the circle due to these point charges? (Express your answer in vector form. Use the following as necessary: ker 9, and r.) E = 3k q ,.2 -j (b) What If? What is the minimum electric field magnitude that could be obtained at the center of the circle by moving one or more of the charges along the circle, with a minimum separation of 3.90° between each of the charges? Express your result as the ratio of this new electric field magnitude to the magnitude of the electric field found in part (a). Eminimum 0.0015 Epart (a) Place the two charges +q at 0 = 270° ±y, where y is the smallest angle at which the charges do not overlap with the charge -2q, then write an expression for the electric field at the center.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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