15. For a triaxial shear test conducted on a sand specimen at a confining pressure of100 kN/m² under drained condition,s resulted in a deviator stress (s₁ - S3) atfailutre of 100 kN/m². The angle of shearing resistance of the solid would be

15. For a triaxial shear test conducted on a sand specimen at a confining pressure of 100 kN/m2 under drained condition,s resulted in a deviator stress (s₁ - $3) at failutre of 100 kN/m². The angle of shearing resistance of the solid would be

15. For a triaxial shear test conducted on a sand specimen at a confining pressure of 100 kN/m2 under drained condition,s resulted in a deviator stress (s₁ - $3) at failutre of 100 kN/m². The angle of shearing resistance of the solid would be

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: A direct shear test was conducted on a dried sand sample in a test box of 60mm x 60mm normal load of…

A: Part A Normal stress = 400/60*60= 0.111N/mm2 Shear Stress= 250/60*60= 0.069 N/mm2 Since it is a sand…

Q: At failure, the major and minor principal stresses on a triaxial test are 200 kPa and 110 kPa…

A: Given data Major principal stress : 200 kpa Minor principal stress :110 kpa Pore water pressure at…

Q: Solve this problem graphically and then analytically. A CU triaxial test was performed on a dense…

A: Introduction Stress is a physiological term in continuum mechanics that describes the internal…

Q: A direct shear test was conducted on a cohesionless soil (c = 0) specimen under a normal stress of…

Q: In a triaxial test at failure, major principal stress was 180 kPa, minor principal stress was 100…

Q: Problem-(5) In a triaxial compression test, the major principal stress was 90 kPa and the minor…

A: Given data- Triaxial Compression test- Major principal stress=90 kPa, Minor principal stress=30 kPa,…

Q: A sample of dry sand is subjected to a tri-axial test. The angle of internal friction is 35.2°. The…

Q: Q.2) In a drained triaxial test carried out on a specimen of clean dry sand failure occurred when…

Q: Friction angle of dry sand is 330. In a direct shear test on this sand, a normal stress of 100kPa…

Q: Q. For a tri-axial shear test conducted on a sand specimen at a confining pressure of 100kN/m² under…

A: Given- Tri-axial shear test- Confining pressure σ3=100 kN/m2Deviator stress σ1-σ3=100 kN/m2It is…

Q: tri-axial shear test conducted on a soil sample having a cohesion of 12 KPa and angle of shearing…

Q: An undisturbed soil sample, 110 mm in diameter and 220 mm in height, was tested in a triaxial…

Q: - In a consolidated-drained triaxial test on a clay, the specimen failed at a deviator stress of…

A: We will use direct formula of principal stress relation.

Q: A sample of dry sand is subjected to a tri- axial test. The angle of internal friction is 37.6°. The…

Q: A CU triaxial compression test was performed on saturated sand at a cell pressure of 100 kPa. The

Q: A triaxial shear test was performed on a well-drained sand sample. The normal stress on the failure…

A: Given Data:In a triaxial testNormal stress on failure plane = 6100 psfShear stress on gailure plane…

Q: sample of dry sand is tested in direct shear. The shear box holding the sample has a circular cross…

Q: A sample of dry sand is subjected to a tri-axial test. The angle of internal friction is 36.8°. The…

Q: 1 .For a direct shear test on a dry sand, the following are given: • Specimen size: 75 mm 75 mm 30…

Q: Samples of damp sand are tested in direct shear (samples are tested at the in situ water content).…

A: Given: For test 1: Normal stress = 50 kPa Shear stress = 33 kPa For test 2: Normal stress = 80 kPa…

Q: For a triaxial shear test conducted on a sand specimen at a confining pressure of 100 kN/m² under…

A: confining pressure σ3=100 kN/m2 Deviator stress- σd=100 kN/m2 Angle of shearing resistance=?

Q: Following data are given for a direct shear test conducted on dry sand: • Specimen dimensions: 75 mm…

A: Given:- The dimension of the specimen = 75 mm ×75 mm×30 mm The normal stress = 250 kN/m2 The shear…

Q: soil specimen (100 mm x 100 mm x 100 mm) is subjected to the forces shown. Determine the following:…

A: As per guidelines we need to answer only first 3 subparts of question so please repost rest…

Q: Triaxial tests performed on samples of aeolin sand. The failure conditions in terms of effective…

A: Given Data: The failure conditions in terms of effective stress are given as:…

Q: A SOmple oJ OJ ary SO WAS tri axial test with a confining pressure of 250 kN/m², The angle of…

Q: In a triaxial unconsolidated undrained (UU) test on a saturated clay sample, the cell pressure was…

A: given cell pressure=100 kPadeviator stress=150 kPa

Q: Friction angle of dry sand is 35°. In a direct shear test on this sand, a normal stress of 150kPa…

A: Given data : Normal stress (σn)=150 KPaFriction angle (ϕ)=35∘The given soil is sandy soil .Hence…

Q: Q3) A consolidated un drained triaxial test was performed on a specimen of saturated clay with a…

A: Given data Confining stress = 20 kpa Deviator stress = 28 kpa Failure angle = 50°

Q: A sample of ocean sand was retrieved from 7 m below the surface. The sample had been under a…

A: Given data - Vertical stress = 150 KN/m² Horizontal stress = 250 KN/m² Shear stress = 86.6 KN/m²…

Q: 5m 3m 2m N.G.L Gs=2.67, e = 0.78 Sand 3 y(sat.) = 18KN/m ³ Silty Clay 20KN Ysat. m3 Gravel

A: step 1-

Q: A sample of dry sand is subjected to a tri- axial test. The angle of internal friction is 34.8°. The…

Q: In a triaxial test at failure, major principal stress was 180 kPa, minor principal stress was 100…

Q: 1). In a series of unconsolidated-undrained triaxial tests on 5. [Shear Strength] speciments of a…

Q: Question A dry sand specimen is put through a triaxial test. The cell pressure is 50 kPa and the…

A: Given data : Cell pressure (σ3)=50 KPaDeviator stress (σd)=100 KPa To Determine: The angle of…

Q: A sand specimen was compacted in a direct shear device and loaded with a vertical stress of 150 kPa.…

A: According to given data . A sand specimen was compacted in a direct shear device and loaded with a…

Q: For a direct shear test on a soil having USCS classification SP, the shear stress at failure was…

A: Soil type = Sp (Poorly graded sand) Shear stress at failure , τ = 45.5 kPa Normal stress at failure,…

Q: A sand sample is subjected to direct shear testing at it's (in - situ) water content. Two tests…

A: Shear Stress, T = 400 KPaNormal Stress, σ = 600KPa. for sand , Cohesion C = 0

Q: In a triaxial tests carried out on a sand sample with cell pressure 20 kPa, the observed value of…

A: Cell pressure = 20 kPaStress at the point of failure = 4 kPaTo Find :The angle of internal friction…

Concept explainers

Test for Determination of Shear Strength

The term shear strength is often associated with the soil. Shear strength is defined as the resistance to the deformation of soil particles due to the continuous action of shear stress. In short, shear strength is the maximum shear stress that a soil can sustain.

Question

15. For a triaxial shear test conducted on a sand specimen at a confining pressure of
100 kN/m² under drained condition,s resulted in a deviator stress (s₁ - S3) at
failutre of 100 kN/m². The angle of shearing resistance of the solid would be

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1: Given data-

VIEW

Step 2: Calculation-

VIEW

Solution

VIEW

Step by step

Solved in 3 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Test for determination of shear strength

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Assume that both a triaxial shear test and a direct shear test are to be performed on a sample of dry sand. When the triaxial shear test is performed, the specimen fails when the major and minor principal stresses are 80 and 20 lbs/in^2, respectively. When the direct shear test is performed, what shear strength can be expected if the normal stress is 4000 lbs/ft^2? Show all work.
Soil
Please be clear in explaining..
Shear Strength In a UU Triaxial compression test on a = 0 soil, failure was observed at a deviatoric stress of 60 kN/m² under a confining stress 50 kN/m2 of the confining stress is increased to 100 kN/m², the deviatoric stress at failure is
How to solve this question?
1.A dry sand is known to have an angle of internal friction of 29. A triaxial test is planned, where the confining pressure will be 41 kPa. What is the maximum axial stress, in kPa, (major principal stress) that can be applied? Calculate the value to 1 decimal place. Do not provide units in your answer. 2.A clay soil is subjected to a triaxial test under unconsolidated-undrained conditions. At failure, the major and minor principal stresses are 8401 psf and 4875 psf, respectively. What is the shear strength of this soil if the confining pressure is doubled? Provide your answer in psf with no decimals.
a sample of dry sand is tested in direct shear. the shear box holding the same has a circular cross section with a diameter of 50 mm. The normal compressive load imposed is 200N. The sample shears when the shear force is 120N. Compute the Normal stress, Shear test at failure Angle ofninternal friction of this soil.
please answer my homework problems. I will leave good review. thank you!
A sample of sand is sheared in the following manner. First an all around normal stresso 350 kPa is applied to the sample. Next a shear stress is applied to the horizontal pia while the normal stress remains constant. The shear stresses at failure are + 186 kPa. Ihe initial stress and stress condition at failure are shown below 350 kPa 350 kPa 186 kPa 350 kPa 350 kPa ー550 kPa 550 kPa 186 kPa 350 kPa 350 kPa Initial Conditions At Failure Determine the Following: fo A) Assuming c, = 0, draw a failure envelope for the soil. Define the friction angle ( the soil. B) Draw the Mohr's Circle at failure for the test. C) Show the location of the pole. D) Define the maximum and minimum principal stresses at failure. E) Define the normal stress corresponding to the maximum shear stress
A sand sample is subjected to direct shear testing. Two tests areperformed. For test 1, The sample shears at a stress of 2500 psf whenthe normal stress is 4000 psf.Test 2, The sample shears at a stress of 3500 psf when the normalstress is 6000 psf. Determine the following:a) Angle of Internal frictionb) Value of cohesionc) Compute the shear stress at a depth of 12 ft. if the unit weight ofthe soil is 150 pcf
Soil sample size is (21cm×21cm)
A soil specimen is subjected to a tri – axial test. The soil specimen is cohesionless. If the shear stress that causes failure is 300 kPa. and the normal stress at failure is only 500 kPa 5. Determine the angle of shearing resistance in degrees 6. Determine the angle that the failure plane measured from the major principal plane. 7. Determine the total axial stress in kPa at which failure is expected to occur.