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- Design a combinational circuit with the four inputs A,B.C, and D, and three outputs X, Y, and Z. When the binary input is odd number, the binary output is one lesser than the input. When the binary input is even number the binary output is one greate than the input. Implement the function using multiplexers with minimal input and select line.Write a VHDL code for the following simple logic circuit. D- X1 X2 f X3USE DIGITAL LOGIC AND DESIGN Part 1: In Figure_4; we have 4-bit Comparator using 2-bit Comparators block. You have to satisfy given condition by applying all data on figure 4. At the end, given condition should produce HIGH output and other two should be LOW. A3 A2 A1 A0 = 1101 and B3 B2 B1 B0 = 1110 Figure_4 Part 2: The serial data-input waveform (Data in) and data-select inputs (S0 and S1) are shown in Figure_5. Determine the data-output waveforms from D0 through D3. Figure_5 Part 3: Decoder can be useful when we have to decode some specific numbers from their equivalent code. Figure 6 has a concept of 3 to 8 line decoder from which you have to generate output waveform from D0 to D7 with proper relationship to input. Figure_6 Part 4: The data-input and…
- H.W :- 1) A four logic-signal A,B,C,D are being used to represent a 4-bit binary number with A as the LSB and D as the MSB. The binary inputs are fed to a logic circuit that produces a logic 1 (HIGH) output only when the binary number is greater than 01102-610. Design this circuit. 2) repeat problem 1 for the output will be 0 (LOW) when the binary input is less than 01112-710- Saleem Lateef1. Gray code to Binary converter: Gray code is one of the codes used in digital systems. It has the advantage over binary numbers that only one bit in the code word changes when going from one number to the next. (See Table 1). Design a combinational circuit with 4 inputs and 4 outputs that converts a four- bit gray code number into an equivalent four-bit Binary number. Use Karnaugh map technique for simplification. Use LogicWorks for pre-lab demonstrations. Select the library "7400dev.clf* in the Parts Palette and then select the XOR chip 74-86. This would give you a set of 4 XOR's as shown in Fig. 1, just like the hardware chip 74-86. You could use as many as needed from these XOR gates in your design. Get back to ALL LIBRARIES and select switches for the inputs and Binary Probes as indicators of the outputs. Verify your design in the pre-Lab. During the Lab construct the circuit and verify its operations.Q6: For the following logic function: F(x,y,z) = xyz + xyz + xyz +xyz a. Draw the logic Circuit b. Construct the Truth Table c. Simplify the Logic Circuit
- Design a logic circuit with four inputs and one output that will produce "l" in the output only if the input patterns have odd number of zeros. a) Write the Boolean equation for the circuit in the simplest SOP form. b) Draw the logic circuit for the above equation in its simplest form. c) Re Design the logic circuit using NANI) gates only?A logic function is expressed by the equation = 0.1.8.9.4. Plot the the values on the K-map below Note: w is the msb (most significant bit) 3 x 10 0- - W X 1 00 01 Write the simplified Sum of Products (SOP) expression. Use yz WIM or "" for NOT; 11 10 for AND; "+" for OR (without the quotation marks.Consider two 8-bit inputs, A = $52 and B = $C3 to the arithmetic and logic unit (ALU). Compute R =A + B. Express R in the hexadecimal form $-- : -61 Express N-Z-V-C bits in the form ----:
- IH.W: Draw a logic eircuit of the following Boolean expression before and after simplification using karnough map and Boolean expression. Y-AB+ AB A B Y 1 1Please design a 6:1 multiplexer following the below procedures with data inputs of D5, D4, D3,D2, D1, D0 and output of Y.1 How many select signals are needed for this Mux.2) List a truth table for this Mux. Note: for all the unused combinations of select signals, Y=D53) Develop an optimized function for this Mux.4) Sketch the logic diagram of implementing this 6:1 Mux.5) Write a complete VHDL structural model to implement the above 6:1 multiplexer. Assume allthe required sub-component (standard gates) VHDL models are given/known that you can useDIGITAL LOGIC DESIGN Are the following addition results Overflow or underflow and why?