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15 SSM ILW A spherical drop of water carrying a charge of 30 PC has a potential of 500 V at its surface (with V = 0 at infinity). (a) What is the radius of the drop? (b) If two such drops of the same charge and radius combine to form a single spherical drop, +241 what is the potential at the surface of the new drop? -341 rec- +492 a

15 SSM ILW A spherical drop of water carrying a charge of 30 PC has a potential of 500 V at its surface (with V = 0 at infinity). (a) What is the radius of the drop? (b) If two such drops of the same charge and radius combine to form a single spherical drop, +241 what is the potential at the surface of the new drop? -341 rec- +492 a

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16e. What is the potential at the location of 4, due to the previous charges? How much work is done to bring in the 4th charge? Make sure you use the correct distance. Volts V14 = Volts V24 = V34 = V4 = V14 + V24 + V34= = 16f. What is the potential at the location work is done to bring in the 5th charge? V15 = Volts V35 = Volts V5 = V15 + V25 + V35 + V45 = V36 = V56 = Volts W6 = Volts Volts V6 = V16 + V26 + V36 + V46 + V56 = V W4 = Joules of 5, due to the previous charges? How much Make sure you use the correct distance. V25 = Volts 16g. What is the potential at the location of 6, due to the previous charges? How much work is done to bring in the 6th charge? Make sure you use the correct distance. V16 = Volts V26 = Volts V45 = V V46 = Volts W5 = Joules V Joules di al 16 Volts hd of snob al = SV V pol 16h. What is the total work done to assemble these charges? This = potential energy U. ΣW = U = Joules
Transcribed Image Text:16e. What is the potential at the location of 4, due to the previous charges? How much work is done to bring in the 4th charge? Make sure you use the correct distance. Volts V14 = Volts V24 = V34 = V4 = V14 + V24 + V34= = 16f. What is the potential at the location work is done to bring in the 5th charge? V15 = Volts V35 = Volts V5 = V15 + V25 + V35 + V45 = V36 = V56 = Volts W6 = Volts Volts V6 = V16 + V26 + V36 + V46 + V56 = V W4 = Joules of 5, due to the previous charges? How much Make sure you use the correct distance. V25 = Volts 16g. What is the potential at the location of 6, due to the previous charges? How much work is done to bring in the 6th charge? Make sure you use the correct distance. V16 = Volts V26 = Volts V45 = V V46 = Volts W5 = Joules V Joules di al 16 Volts hd of snob al = SV V pol 16h. What is the total work done to assemble these charges? This = potential energy U. ΣW = U = Joules
**15 SSM ILW A spherical drop of water carrying a charge of 30 PC has a potential of 500 V at its surface (with V = 0 at infinity). (a) What is the radius of the drop? (b) If two such drops of the same charge and radius combine to form a single spherical drop, what is the potential at the surface of the new drop? -341 +291 16 Go Figure 24-37 shows a rec- tangular array of charged particles fixed in place, with distance a = 39.0 cm and the charges shown as integer multiples of q₁ = 3.40 pC and q2 = q1 6.00 pC. With V = 0 at infinity, what la 1 +492 +291 -91 +492 Figure 24-37 Problem 16.
Transcribed Image Text:**15 SSM ILW A spherical drop of water carrying a charge of 30 PC has a potential of 500 V at its surface (with V = 0 at infinity). (a) What is the radius of the drop? (b) If two such drops of the same charge and radius combine to form a single spherical drop, what is the potential at the surface of the new drop? -341 +291 16 Go Figure 24-37 shows a rec- tangular array of charged particles fixed in place, with distance a = 39.0 cm and the charges shown as integer multiples of q₁ = 3.40 pC and q2 = q1 6.00 pC. With V = 0 at infinity, what la 1 +492 +291 -91 +492 Figure 24-37 Problem 16.
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Electric potential at the surface of a sphere:

The electric potential (V) at the surface of a sphere is given by the equation,

V equals fraction numerator k q over denominator R end fraction   

where k is the Coulomb's constant, q is the total charge on the sphere, and R is the radius of the sphere.

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