15) n(n*+5) is divisible by for each integer

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter8: Sequences, Series, And Probability
Section8.5: Mathematical Induction
Problem 27E
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Are there a way where I can turn 6d = k(k^2 + 5) to 6 ( an integer ) = k+1 ((k+1)^2 + 5)?
15)
for each
n(n*+5) is divisible by o
integer
Proof (ay induction)
PO)= "o (0?+5) is divisible by 6"? 610 =0 since
6.0 = 0 V
P(x) > P(Kti): Let KE ə k20
Assume
PCK) is true
"K (K?+5) is divisible by
that is,
So this.mean that
6d = k(K?+5) for some
definition
of divisi bility.
intoger d.by
NTS: kti((K+)*+5) is divisible by 6
61 KHI ((K+i)?+5)d= ktH ((K+)45)
%3D
Now,
od = K(K?+5),)
Transcribed Image Text:15) for each n(n*+5) is divisible by o integer Proof (ay induction) PO)= "o (0?+5) is divisible by 6"? 610 =0 since 6.0 = 0 V P(x) > P(Kti): Let KE ə k20 Assume PCK) is true "K (K?+5) is divisible by that is, So this.mean that 6d = k(K?+5) for some definition of divisi bility. intoger d.by NTS: kti((K+)*+5) is divisible by 6 61 KHI ((K+i)?+5)d= ktH ((K+)45) %3D Now, od = K(K?+5),)
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