14. In aqueous solution, hydrazine is a base that can accept two protons:N₂H4(aq) + H₂O(l) ≥ N₂H5†(aq) + OH-(aq)Kb1 = 8.5 x 10-7N₂H5+ (aq) + H₂O(1) ≥ N₂H6²¹(aq) + OH-(aq) Kb2 = 8.9 x 10-16a. What is the pH of a 0.015 mol.L-¹ hydrazine solution? |b. What is the concentration of N2₂H4, N₂H5†, and N₂H6²+ at equilibrium?

Since Kb2 << Kb1, the OH-(aq) contribution is mainly due to the 1st hydrolysis reaction. Hence…

14. In aqueous solution, hydrazine is a base that can accept two protons: N₂H4(aq) + H₂O(1) ≥ N₂H5†(aq) + OH-(aq)_____ Kb1 = 8.5 x 10-7 N₂H5+ (aq) + H₂O(1) ≥ N₂H6²†(aq) + OH-(aq) Kb2 = 8.9 x 10-16 What is the pH of a 0.015 mol.L-¹ hydrazine solution? | b. What is the concentration of N₂H4, N2H5†, and N₂H6²+ at equilibrium?

14. In aqueous solution, hydrazine is a base that can accept two protons: N₂H4(aq) + H₂O(1) ≥ N₂H5†(aq) + OH-(aq)_____ Kb1 = 8.5 x 10-7 N₂H5+ (aq) + H₂O(1) ≥ N₂H6²†(aq) + OH-(aq) Kb2 = 8.9 x 10-16 What is the pH of a 0.015 mol.L-¹ hydrazine solution? | b. What is the concentration of N₂H4, N2H5†, and N₂H6²+ at equilibrium?

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter15: Acid–base Equilibria

Section: Chapter Questions

Problem 7P

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