14 8.5 + 9 8 Shape width equals 6 units.

Give the following problem a try. If you get stuck, here is one way to work it: Essential Solution Video. For the shape below, assume the following dimensions: a = 175 mm b = 220 mm d = 300 mm t = 23 mm The centroid of this shape is located 71.762 mm to the right of point H shown in the figure. What is the moment of inertia ly about the y centroidal axis for this shape? H Answer: ly M b 2t mm4

This is an exercise to illustrate the effects of mesh refinement on a 1-d rod. To estimate the self-weight elongation (8) of the tapered conical rod shown in the figure. The diameter varies linearly from Do at the bottom to aDo at the top, where 0.1 < E Young's Modulus y Unit weight (Diameter at top) 8 clongation D (Diameter at bottom) a<0.5. Solve for L= 5m, y= unit weight of steel, E= young's modulus of steel, Do=3m and a=0.3. Solve the problem at least four times using an increasing number of rod elements (nels=2, 4, 6, 8). Make appropriate assumptions about how to deal with the changing cross-sectional area and self-weight loading along the length of the rod. A plot of the dimensionless tip deflection SE/yL? vs. number of elements (nels) used in the discretization to show convergence on the exact solu- tions of

Mc A B For the beam shown in the figure, with the depicted loading and boundary conditions, draw the shear force and bending moment diagrams – please draw your graphs with care to represent constant values, linear relationships and parabolic relationships. In your work show the reactions and respective values at A and B, the equations you obtained for shear force and bending moment distributions, and relevant values of shear force and bending moment at relevant points along the span of the beam – in your graphs. Mc = 4 kN.m P = 3 kN/m L = 1.25 m