13)The Beam in figure below is weightless. A moveable weight(mass)W of 300 lbm is to be attached as shown. 420 ibf 640 lbf -3.0 ft 6.0 ft 6.0ft B a) Draw the FBD and show all the forces. b) Calculate force for weight(mass) W. gl= 32.174 ft/s? c) Determine summation of forces in Y direction and X direction and set-0 (EF,=0, EF,=0)

Two couples act on the beam (Figure 1). Figure 1.30 200 lb 28 200 b 1 of 1 > Part A F = 137 lb, determine the resultant couple moment. Express your answer to three significant figures and include the appropriate units. ▸ View Available Hint(s) M- Value Submit Provide Feedback Units ?

Notes: 1) ‘replace … by an equivalent resultant force and couple moment at point O’ really just means ‘find the resultant force and moment about point O’. 2) Wrenches ≡ 3D couples, here represented by blue double-headed arrow and light blue curved arrow.   Please show/provide all written work.

A:0. docs.google.com/forms/d/e/1FAlpQLSeE : مطلوب Untitled Se F1 =5 kN F2 = 13 kN 45 B = 60 F3 = 4 kN 4 m 8 m D F4 = 22 kN a = 30° FS = 4 kN Vhat is the resultant moment of the five forces acting on the rod about point B? 0.5 kN.m b) 49.5 kN.m c) 39.1 kN.m d) 18.5 kN.m e) 9.1 kN.m f) 21.1 Vhat is the resultant moment of the five forces acting on the rod about point E? 22.8 kN.m b) - 2.8 kN.m c) – 18.9 kN.m d) - 8.1 kN.m - 12.7 kN.m f) -7 Vhat is the moment of the force F1 about point D? 27.8 kN.m b) - 12.8 kN.m c) - 38.9 kN.m d) - 19.1 kN.m e) - 32.7 kN.m f) - 29 Vhat is the moment of the force F2 about point E? .5 kN.m b) 55.5 kN.m el 14.2 kN.m d1 32.5 kN.m el 7.1 kN.m. A 84.1