13-47 A dryer is shaped like a long semicylindrical duct of diameter 2 m. The base of the dryer is occupied with water-soaked materials that are to be dried. The dome of the dryer has a constanttemperature of 500°C, while the materials at the base are at 40°C. Both surfaces can be approximated as blackbodies. Determine the length of the dryer so that the materials are dried at a rate of 0.1 kg/s.FIGURE P13–47Tz = 500°C------D= 2.0 m -T = 40°C

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Answered: 13-47 A dryer is shaped like a long…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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Determine the view factors F13 and F23 between the rectangular surfacesshown. (Answer: F13 = 0.26, F23 = 0.06)
determine the view factor, and the net heat transfer by radiation between two gray surfaces, A (εA= 0.88) and B (εB= 0.65) at temperatures 450°C and 50°C, respectively if d. surfaces A and B concentric cylindrical tubes with diameters of 400 mm and 200 mm, respectively e. both surfaces are discs of diameter 3 m one exactly above the other, 1 m apart
A furnace is located next to a dense array of cryogenic fluid piping. The ice-covered piping approximates a plane surface with an average temperature of Tp = 0°C and a total, hemispherical emissivity of εp = 0.53. That is, the piping can be replaced by a flat surface with the given properties. The furnace wall has a temperature of Tf = 206°C and a total, hemispherical emissivity of εf = 0.83. To minimize the heat loading on the regirgeration equipment and piping, a reflective aluminum radiation shield with a total, hemispherical emissivity of εs = 0.14 on each of its sides is installed between the pipiing and the furnace wall as shown. Assume that all surfaces are diffuse and gray and treat the problem as one-dimensional (surfaces form infinite parallel plates). What is the heat load on on the refrigeration unit? That is, what is the net radiative power at the surface which approximates the dense array of ice-cold piping, qrad,p in Watts?
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Wien's law is stated as follows: AmT = C, where C is 2898 μmK and Am is the wavelength at which the emissive power of a black body is maximum for a given temperature T. The spectral hemispherical emissivity (Ex) of a surface is shown in the figure below (1Å= 10-¹0m). The temperature at which the total hemispherical emissivity will be highest is K (round off to the nearest integer). Ext n 5000 6000 7000 (A)
Calculate the absorbed irradiation by the surface in W/m2
On a clear night, when the effective blackbody temperature of the space is - 30°C, the air contains water vapor at a partial pressure equal to that of ice or liquid water at 0°C. A very thin film of water, initially at 20°C, is placed in a very shallow well-insulated pan, placed in a spot sheltered from the wind with a full view of the sky. If hc = 2.6 W/m². °C, state whether ice will form, supporting the conclusion with suitable calculations.
Please answer the questions below.
For a surface, how is irradiation defined? For diffusely incident radiation, how is irradi ation on a surface related to the intensity of incident radiation?
Question 30 of 30 く - / 4.3 View Policies Current Attempt in Progress Two concentric spheres of diameter D = 0.8 m and D2 = 1.2 m are separated by an air space and have surface temperatures of T = 410 K and T2 = 300 K. (a) If the surfaces are black, what is the net rate of radiation exchange between the spheres, in W? 912 = W (b) What is the net rate of radiation exchange between the surfaces if they are diffuse and gray with &j = 0.5 and ɛ2 = 0.05, in W? 912 = i W (c) What is the net rate of radiation exchange if D2 is increased to 20 m, with ɛ2 = 0.05, ɛ = 0.5, and D = 0.8 m, in W? 912 = W (d) What is the net rate of radiation exchange if the larger sphere behaves as a black body (ɛ2 = 1.0) and with &j = 0.5, D2 = 20 m, and D = 0.8 m, in W? 912 = i W Physical Properties Mathematical Functions II

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