= -130 + 60t - 4t², where An object moves according to the equation I I is its position, in kilometres [N] and t is the time in hours. %3D

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Pls help ASAP. Pls look at both images. 

An object moves according to the equation T =-130 + 60t- 4t², where
I is its position, in kilometres [N] and t is the time in hours.
Question 3
a) It is correct to say that, during its entire motion,
the object's speed is constant.
O the object's speed is decreasing.
the object's acceleration is constant.
O the object's speed is increasing.
Question 4
b) The object's position 4 hours after the start of its motion is
O 23 km [S).
O 23 km (N).
O46 km [N].
O 46 km [S].
Transcribed Image Text:An object moves according to the equation T =-130 + 60t- 4t², where I is its position, in kilometres [N] and t is the time in hours. Question 3 a) It is correct to say that, during its entire motion, the object's speed is constant. O the object's speed is decreasing. the object's acceleration is constant. O the object's speed is increasing. Question 4 b) The object's position 4 hours after the start of its motion is O 23 km [S). O 23 km (N). O46 km [N]. O 46 km [S].
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