13. How big would a square solar sail need to be in order for sunlight to exert a 15 N force on it (use 1,100 W/m² as the intensity of the sunlight).
Q: 10. Determine the x and y component of the vector 30 N, 30° North of East
A: The force is F = 30 N 30° North of East
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A:
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A: Magnitude of p = 7 Magnitude of q = 2 Angle, θ = 150°
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A:
Q: Find the order of magnitudes of the three numbers below. a. 35243 z ? b. 0.081 × ? C. 0.00021 × ?
A: Since there are multiple questions posted, we will answer the first question. The order of magnitude…
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A:
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A: Given value--- firstly driven 1.25 km south, then 8.75 km in a direction 57° north of east. We…
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A: Ans; 35.102 unit2 Explanation:Step 1:
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A:
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Q: Figure 1 B (15.0 m) Ď (10.0 m) 30.0 53.0 25.0 Ĉ (12.0 m) Á (8.00 m)
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A: Given: the direction of velocity and the strength of magnetic field is given.
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A: F1 = 4.90 N due north F2 = 9.80 N due south west
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A:
Q: Ã = (5 m/s)î + (2 m/s)j, B = (3 kg · m/s²)î + (2 kg · m/s²)I %3D
A:
Q: 1. Find the unit vector in the direction w^ = 6^ - 2j^
A: The unit vector in the direction of w→=6 i^-2 j^. Given, w→=6 i^-2 j^
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A: Given, A vector A Let A vector=xi+yj its negative vector B=-xi-yj
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Q: Part C Enter the expression -20 + 6D in the answer box using the notation just described. Express…
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Q: Draw the vector
A: vectors(2d) can be represented in sheets or plane by drawing with proper magnitude and direction.
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A: Given,Magnitude of the vector, R = 5 NAngle with the horizontal or with x - axis, θ = 36.80°
Q: its not 2.42
A:
Q: A force 4 N making angle 45 with x axis. The y component is?
A: Answer Given Force F = 4 N Angle θ = 45º with x axis we have to find y component.
Q: Find a unit vector â parallel to the vector A = 41 – 3 j
A: Find a unit vector â parallel to the vector A = 41 – 3 j
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A: 1st part solution:
Q: Ā = 3î + 43, B = î + 2)
A:
Q: 1. Calculate the resultant vector based on the information given in figure 1. Old 50.0 N 60.0⁰ 30.0⁰…
A: See below
Q: Question 6
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Q: 250 N the magnitude and dire 400 N 300 N Torce.
A:
Q: A boat travels on a course of bearing N 37 degree 109 W for 79.5 miles. How many miles north and how…
A: Given: The direction of the boat is N37o109'W=N 37o+109'×1o60' W=N 37o+109'×1o60' W=N38.82oW The…
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