*13. Determine V, and ID for the network of Fig. 2.142. +10 Vo 2 k2 2 k 2 k
Q: For the circuit shown, R1 = 23.37 0, R2 = 11.61 0, V emf,I = 21.01 V, and V emf,2 = 10.75 V.…
A:
Q: Ex. 1: A cuurent of 800 mA is passed through an electric lamp for a minute. Find the number of…
A: We have to find- number of electrons (n)=? The data given as- Current through lamp=800 mA=0.8 A…
Q: A conductor has a cross-sectional area of 2.3×106 m² and the number of free electrons per unit…
A: Cross-sectional area is A = 2.3×10-6 m2 Electron density is n = 8.5×1028 electron/m3 Current, I =…
Q: Using Excel and the data for the light bulb, plot V vs i, with the equation for the trendline…
A: Ohm's law gives the relation connecting voltage and current. Ohm's law states that the voltage…
Q: IRZ E₂ R2 Σ 3.00 ΚΩ 2.00 ΕΩ a www R₁ Ⓡ the current (in mA) in each resistor shown in the figure…
A:
Q: If 5.0 x 1021 electrons pass through a 42.3 2 resistor in 10 min, what is the potential difference…
A:
Q: Determine the magnitude of the current flowing through a 4.7 k2 resistor if the voltage across it is…
A: “Since you have posted a question with multiple sub-parts, we will solve the first three sub-parts…
Q: 1. Use nodal analysis to determine the node voltages v, and v2 in the circuit below. (Ans. ₂-0 V, ₂=…
A:
Q: What is the resistance (in units of 0) of a wire made of a material with a resistivity of 3.2 x 10-8…
A: The resistance Rof a wire of length l, cross secetion area A, and resistivity ρ, is given by,R=ρlA
Q: A thermometer made of Platinum has a resistance of 502 at 20 C what is the measured temperature (in…
A: Given:- R1 = 50Ω , t1 = 20oC R2 =79.2Ω , t2 = ? temperature coefficient (α) = 3.92 *10-3 C-1
Q: a- Calculez les intensités Ii et l2 parcourant chacun des deux conducteurs.
A: Resistances R1 and R2 are in parallel. So, both resistances experience same potential 200 V.…
Q: 6. a) A 240 V lamp draws a current of 0.50 A from the mains supply. What is the resistance of the…
A: a. Given data The voltage is given as V = 240 V. The current is given as I = 0.5 A. The resistance…
Q: V(v) I(mA) R=V/I 1 2 1 2 4 4 1 3 6 6 1 8 8 1 5 10 1 2. 10 4)
A: BY Ohm's law we get R=V/I Ohm's law states the relationship between potential voltage and current.…
Q: An electric heater is constructed by applying a potential difference of 108.4V across a wire with a…
A: Given, Potential difference V = 108.4 V Resistance R =5 ohms We know the expression for power is…
Q: If 5.0 × 1021 electrons pass through a 32.5 Q resistor in 10 min, what is the potential difference…
A:
Q: wwwww Port Aneeds me to find the potential of port a with respect to ponto in the figure
A:
Q: Determine the equivalent resistance between terminals a and b. R1 a ww 7 Ohms b O 10.0117 Q O 9.9874…
A:
Q: A silver wire 4 mm in diameter transfers a charge of 12-mC in 8 minutes. Silver contains 5.8 × 1028…
A:
Q: Determine the equivalent resistance between terminals a and b 6.3498 Q O 6.3333 Q O 6.27140 O 6.2987…
A:
Q: If 5.0 × 1021 electrons pass through a 32.5 Q resistor in 10 min, what is the potential difference…
A:
Q: Using ohm's law, determine how much electrical current will flow through this circuit. Your answer…
A: The electric current through the circuit is given by I=VReq Here, V is the voltage of the source and…
Q: 3. Two resistors a and b are connected in parallel. The total resistance R in such a circuit is…
A:
Q: A thermometer made of Platinum has a resistance of 50 N at 20 C, what is the measured temperature…
A:
Q: 6. A 10.0 μF capacitor is charged to 120 V and is then connected across a 520 resistor only. What is…
A:
Q: Determine v, through v4 in the circuit in Fig. 2.75. V2 12 V + 8 V - - 6 V + 10 V V4 V3 +
A: In the given circuit, We have to determine the values of v1 through v4.
Q: A conductor has a cross-sectional area of 2.3x106 m2 and the number of free electrons per unit…
A: Given:- I = 16.5 A free electron density (n) = 8.5 *1028 electrons/m3 charge of electron (e) =…
Q: a. Find Vab and io in the circuit in Fig. 3 20 S2 30 2 80 V 20 Ω 30 N ww 30 2 80 V 20 2 Fig. 3 www
A: use Kirchoff's second rule to the circuit. apply voltage rule to loop ABCDA…
Q: 1)lf 6.24 x1018 electrons pass through a wire in 1 s, how many pass through it during a time…
A: Answer...
Q: 1.9. A block of conductor has the dimensions Lo x 2Lo x 4Lo. As shown in the figure below, the same…
A: Resistance of any conductor depends on its material, length and cross sectional area. R=ρLA The…
Q: Consider the circuit shown in the diagram 50.00 7.0V Use Kirchhoff's junction rule at junction b to…
A: Given: I1=0.3 A The circuit diagram is given below.
Q: Q2. a). Find the voltage, Vs in the electric network shown in figure B, 4mA Vs R₁ = 3 k www V₁ + Is…
A: Here current flowing through the whole circuit is 4mA as provided by the current source. As per…
Q: During 33 seconds of use, 340 C of charge flow through a microwave oven. Compute the size of…
A: Current is defined as rate of flow of charge, I = Q/t
Q: Problem 2.25: Find io, i and i2. 24 Ι 2Ω 10 Ω VA 0.81. 20 Ω ΣΩ
A: The value of v∆ is calculated by using voltage division rule. v∆=24×10 10+2v∆=20 V Apply Kirchhoff…
Q: Ex. 60: A potentiometer wire of length 10 m and resistance 9 Q is connected to a battery of e.m.f.…
A: To find- (1)Potential gradient a long the wire VL=?(2)Balancing length for cell of e.m.f 1.08…
Q: Q1. Find the following: a. ZT b. VR C. V d. IT VR Ve 17 10 Q X = 20 0 15 V/0° Xc = 30 VoTX = 70
A: AC response of a Resistance: Let a voltage v = V0 sin ωt has been applied across a resistance R.…
Q: Q.1. Calculate the node voltages V1 and V2. (40 P) 20V V2 wwww 4 ohm 5 ohm 12A °10 ohm 5 ohm 5 ohm -…
A:
Q: A conductor has a cross-sectional area of 2.3×10-6 m² and the number of free electrons per unit…
A: The given values are, A=2.3×10-6 m2n=8.5×1028 /m3I=12.3 AQ=1.6×1019 C
Q: In the figure, E1= 10 V and E2= 24 V. The resistances are each 4 N. What are potentials Vị and V2?…
A: Given : E1 = 10 V , E2 = 24 V
Q: 2. A battery has a charge of 3.5mC. It has an initial EP of 600V which moves to the final EP with…
A: Given Charge is q=3.5×10^-3 C Potential difference is =800 V-600 V= 200 V
Step by step
Solved in 3 steps with 2 images
