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A: option (b) is correct. see below the calculation
Calculus I
Evaluate the
Step by step
Solved in 3 steps
- If y = (5x + 1)(2x¬1 – In 7), then y' will be A. (5x + 1) (+;) + 5(2x¬1 – In 7) B. (5x + 1) (-) 2. + 5(2x-1 – In 7) c - ÷) + 5(2x-+ – In 7) (5x + 1) (-2x² + 1) (-) 2 + 5(2x¬1 – In 7) D. (5x X'If y = (5x + 1)(2x-1 – In 7), then y' will be A. (5x + 1) (+;) + 5(2x-1 – In 7) B. (5x + 1) (-)- + 5(2x¬1 – In 7) C. (5x + 1) (-2x² -;) + 5(2x-1 – In 7) D. (5x + 1) (;-) + 5(2x-1 – In 7)6) Show the equivalent of (2x + 3y)(4x² - 6xy +9y²) + (2x − 3y)(4x² + 6xy +9y²) 16x³ for x # 0. (