1)^3 , 1 ≤ x ≤ 2, S(x) = S1(x)

Consider the function f(x) = 6 – 2x on the interval [- 2, 8]. Find the average or mean slope of the function on this interval, i.e. f(8) – f( – 2) 8 - (– 2) By the Mean Value Theorem, we know there exists a c in the open interval ( – 2, 8) such that f'(c) is equal to this mean slope. For this problem, there is only one c that works. Find it.

let f(x)={x^2+2, x >-1 AND -x^2-x, x less than for equal to -1} compute f(0), f(-1)and f(-2) a. 0, 2, 6 b. 2, 0, 6 c. 2, 2, 6 d. 2, 0, -2 e. 0, 1, -2