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1=2m w=3m LI=6 m Length = 6 m Width = 9 m Height = 9 m Length = 2 m Width = 3 m Height = 3 m SA-w + w+Ih + Ih ► wh + wh] SA=w +[w+ [Ih + (Ih + wh + wh SA= (6)(9) + (6)(9) + (6)(9) + (6)(9) + (9)(9) + (9)(9) SA= (2)(3) + (2)(3) + (2)(3) + (2)(3) + (3)(3) + (3)(3) SA= (54) + (54) + (54) + (54) + (81) + (81) SA= (6) + (6) + (6) + (6) + (9) + (9) SA= 378 m2 SA= 42 m? h=9m

1=2m w=3m LI=6 m Length = 6 m Width = 9 m Height = 9 m Length = 2 m Width = 3 m Height = 3 m SA-w + w+Ih + Ih ► wh + wh] SA=w +[w+ [Ih + (Ih + wh + wh SA= (6)(9) + (6)(9) + (6)(9) + (6)(9) + (9)(9) + (9)(9) SA= (2)(3) + (2)(3) + (2)(3) + (2)(3) + (3)(3) + (3)(3) SA= (54) + (54) + (54) + (54) + (81) + (81) SA= (6) + (6) + (6) + (6) + (9) + (9) SA= 378 m2 SA= 42 m? h=9m

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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1.What is the scale factor that was used to reduce the dimensions of the left figure compared to the right?

 

2.What would be the effect of this scale factor in the surface areas of the two figures?

 

Problem 3: Two prisms are shown below with different dimensions I-2 m w=3m LI=6m Length = 6 m Width = 9 m Height = 9 m Length = 2 m Width = 3 m Height = 3 m SA=w + (w+ Ih + Ih + wh + wh SA= (6)(9) + (6)(9) + (6)(9) + (6)(9) + (9)(9) + (9)(9) SA= (2)(3) + (2)(3) + (2)(3) + (2)(3) + (3)(3) + (3)(3) SA= (54) + (54) + (54) + (54) + (81) + (81) SA= (6) + (6) + (6) + (6) + (9) + (9) SA= 378 m? SA= 42 m² 1. What is the scale factor that was used to reduce the dimensions of the left figure compared to the right? 2. What would be the effect of this scale factor in the surface areas of the two figures?
Transcribed Image Text:Problem 3: Two prisms are shown below with different dimensions I-2 m w=3m LI=6m Length = 6 m Width = 9 m Height = 9 m Length = 2 m Width = 3 m Height = 3 m SA=w + (w+ Ih + Ih + wh + wh SA= (6)(9) + (6)(9) + (6)(9) + (6)(9) + (9)(9) + (9)(9) SA= (2)(3) + (2)(3) + (2)(3) + (2)(3) + (3)(3) + (3)(3) SA= (54) + (54) + (54) + (54) + (81) + (81) SA= (6) + (6) + (6) + (6) + (9) + (9) SA= 378 m? SA= 42 m² 1. What is the scale factor that was used to reduce the dimensions of the left figure compared to the right? 2. What would be the effect of this scale factor in the surface areas of the two figures?
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