1=2m w=3m LI=6 m Length = 6 m Width = 9 m Height = 9 m Length = 2 m Width = 3 m Height = 3 m SA-w + w+Ih + Ih ► wh + wh] SA=w +[w+ [Ih + (Ih + wh + wh SA= (6)(9) + (6)(9) + (6)(9) + (6)(9) + (9)(9) + (9)(9) SA= (2)(3) + (2)(3) + (2)(3) + (2)(3) + (3)(3) + (3)(3) SA= (54) + (54) + (54) + (54) + (81) + (81) SA= (6) + (6) + (6) + (6) + (9) + (9) SA= 378 m2 SA= 42 m? h=9m

1.What is the scale factor that was used to reduce the dimensions of the left figure compared to the right?

2.What would be the effect of this scale factor in the surface areas of the two figures?