1200 N 800 N 400 N D 2 m B A K J 2 m E 2 m 2 m G 2 m H Using Method of Sections (one cutting section and two equations only), determine the internal force on: round off to two (2) decimal places include negative sign (-) if the answer is Compression ex. -1.500, if in Tension, ex. 1.500

1200 N 800 N 400 N D 2 m B A K J 2 m E 2 m 2 m G 2 m H Using Method of Sections (one cutting section and two equations only), determine the internal force on: round off to two (2) decimal places include negative sign (-) if the answer is Compression ex. -1.500, if in Tension, ex. 1.500

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Axial Load

When a bar of the uniform cross-section is acted by a load, such that the load acts along the longitudinal axis of the bar, such kinds of loadings are known as axial loadings. In general terms, a load is an external force acting on a component. An axial load acts perpendicular to the geometric cross-section of the component. Based on the direction of the application of the load, an axial load can be tensile or compressive. The analysis of bodies under the action of axial loads is generally studied under the branch of mechanics, known as statics.

Question

Write the solution for the following:

Member BC= 600 N

Member FG = -600 N

1200 N
800 N
400 N
D 2 m
C
B
Α,
K
J
2 m
E
2 m
2 m
G
2 m
H
Using Method of Sections (one cutting section and two equations only), determine the internal force on:
round off to two (2) decimal places
include negative sign (-) if the answer is Compression ex. -1,500, if in Tension, ex. 1,500

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