1200 kg 12.0 m/s 40.0 m- 1800 kg 20.0 m/s

Need help with parts (d) and (e). Answers to (a), (b), and (c) are 40 m/s, -72 Ns, and 72 Ns, respectively.

Two balls each have a mass of 4.50-kg. They are positioned on the y axis at 1.00 and 9.00 m, respectively; a third ball with a mass 2.30 kg is located at 6.00 m. Calculate the location of the center of mass of this system?

Enet = The vector position of a 3.80 g particle moving in the xy plane varies in time according tor, = (3î + 3j)t + 2ĵt2 where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.35 g particle varies as 2 sr, = 3î – 2ît? - 6jt. (a) Determine the vector position (in cm) of the center of mass of the system at t = 2.40 s. rcm 4.744i – 7.38j cm (b) Determine the linear momentum (in g• cm/s) of the system at t = 2.40 s. p = 11.4i – 35.58j g• cm/s (c) Determine the velocity (in cm/s) of the center of mass at t = 2.40 s. 1.245i – 3.888j cm/s = cm (d) Determine the acceleration (in cm/s2) of the center of mass at t = 2.40 s. 0.6775j cm/s? = cm (e) Determine the net force (in µN) exerted on the two-particle system at t = 2.40 s. µN