12.71 Air flows steadily through a length ( denotes inlet and 2 denotes exit) of insulated constant-area duct. Prop- erties change along the duct as a result of friction. (a) Beginning with the control volume form of the first law of thermodynamics, show that the equation can be reduced to V² m+ 1 = ·m₂ + 2 2 (b) Denoting the constant by ho (the stagnation enthalpy), show that for adiabatic flow of an ideal gas with friction To T constant k-1 =1+ + k=¹M² 2 (c) For this flow does results. To, To? Po, Po? Explain these =

12.71 Air flows steadily through a length ( denotes inlet and 2 denotes exit) of insulated constant-area duct. Prop- erties change along the duct as a result of friction. (a) Beginning with the control volume form of the first law of thermodynamics, show that the equation can be reduced to V² m+ 1 = ·m₂ + 2 2 (b) Denoting the constant by ho (the stagnation enthalpy), show that for adiabatic flow of an ideal gas with friction To T constant k-1 =1+ + k=¹M² 2 (c) For this flow does results. To, To? Po, Po? Explain these =

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Fluid Dynamics

The study of the flow of gases and liquids, usually in and around solid surfaces, is known as fluid dynamics in physics and engineering. Fluid dynamics, for example, can be used to evaluate the movement of air through an airplane wing or the surface of a vehicle. It can also be used in ship design to increase the speed at which ships pass through water.

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12.71 Air flows steadily through a length ( denotes inlet
and 2 denotes exit) of insulated constant-area duct. Prop-
erties change along the duct as a result of friction.
(a) Beginning with the control volume form of the first law
of thermodynamics, show that the equation can be
reduced to
V²
m+ V² = m₂ + constant
2
(b) Denoting the constant by ho (the stagnation enthalpy),
show that for adiabatic flow of an ideal gas with friction
To
T
=1+
k-1
2
-M²
=
(c) For this flow does To, To? Po, Po₂? Explain these
results.

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