Homework Help is Here – Start Your Trial Now!
Math
Calculus
12. If a b = √3 and a × b = (1,2,2), find the angle between a and b.

12. If a b = √3 and a × b = (1,2,2), find the angle between a and b.

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter8: Applications Of Trigonometry
Section8.4: The Dot Product
Problem 9E
See similar textbooks
icon
Related questions
Question
### Problem 12: Finding the Angle Between Vectors Given the following conditions: - The dot product of vectors \(\vec{a}\) and \(\vec{b}\) is \(\vec{a} \cdot \vec{b} = \sqrt{3}\), - The cross product of vectors \(\vec{a}\) and \(\vec{b}\) is \(\vec{a} \times \vec{b} = \langle 1, 2, 2 \rangle\), Find the angle between vectors \(\vec{a}\) and \(\vec{b}\). #### Solution: - Start by understanding the dot product, which is given by: \[ \vec{a} \cdot \vec{b} = |\vec{a}| |\vec{b}| \cos \theta \] where \(\theta\) is the angle between \(\vec{a}\) and \(\vec{b}\). - The magnitude of the cross product \(\vec{a}\times\vec{b}\) is given by: \[ |\vec{a} \times \vec{b}| = |\vec{a}| |\vec{b}| \sin \theta \] Here, \(|\vec{a} \times \vec{b}| = \sqrt{1^2 + 2^2 + 2^2} = \sqrt{9} = 3\). - Use the relationships between the dot product and cross product to find the angle \(\theta\). This problem illustrates fundamental vector operations crucial for understanding physics and engineering concepts such as force, momentum, and more.
Transcribed Image Text:### Problem 12: Finding the Angle Between Vectors Given the following conditions: - The dot product of vectors \(\vec{a}\) and \(\vec{b}\) is \(\vec{a} \cdot \vec{b} = \sqrt{3}\), - The cross product of vectors \(\vec{a}\) and \(\vec{b}\) is \(\vec{a} \times \vec{b} = \langle 1, 2, 2 \rangle\), Find the angle between vectors \(\vec{a}\) and \(\vec{b}\). #### Solution: - Start by understanding the dot product, which is given by: \[ \vec{a} \cdot \vec{b} = |\vec{a}| |\vec{b}| \cos \theta \] where \(\theta\) is the angle between \(\vec{a}\) and \(\vec{b}\). - The magnitude of the cross product \(\vec{a}\times\vec{b}\) is given by: \[ |\vec{a} \times \vec{b}| = |\vec{a}| |\vec{b}| \sin \theta \] Here, \(|\vec{a} \times \vec{b}| = \sqrt{1^2 + 2^2 + 2^2} = \sqrt{9} = 3\). - Use the relationships between the dot product and cross product to find the angle \(\theta\). This problem illustrates fundamental vector operations crucial for understanding physics and engineering concepts such as force, momentum, and more.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 3 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer