12. Assume a uniformly load simply support beam with a rectangular cross section. The width of the beam is fixed by other design considerations. Determine the ratio between the difference in depth required for an aluminum beam compared to a steel beam in order to obtain the same maximum deflection. MOE aluminum can be taken as 10,000 ksi, for steel as 30,000 ksi. The maximum deflection for the beam is 5wl*/384EI Factoring the deflection equations we can conclude that for equal deflection Eala = Esls where %3D subscripts a and s represent values for aluminum and steel. The depth of must be times the depth of the

PROBLEM 01: Hollow bar length is 1.40m long and tube length is three-fourth as long as the bar. Torque T=1100N.m acts at the free end of the bar. Both the bar and tube are made of an aluminum alloy with shear modulus of w ww elasticity G=27GN/m². Given that dl=35mm, d2=45mm, d3=60mm, d4=70mm. Determine the following: a. Maximum shear stress in both the bar and tube b. Angle of twist at the end A of the bar. (In degrees) Tube Fixed plate End plate Tube d3 d1 d2 d4 Bar Cross-section of the bar and tube

Calculate the maximum deflection of a uniformly loaded simple beam having a span length L=2m, the intensity of uniform load q=2KN/m and the maximum bending stress is 60mpa.The cross section of beam is square,and the material is aluminum having modulus of elasticity E=70Gpa

An alloy steel specimen of 30 mm diameter with a gauge length of 200 mm is load tested. It has extension of 0.16 mm under a load of 85 kN. Load at elastic limit is 160 kN. Young's modulus of the specimen in GPa O 127 O 143 O 150 O 172