12 V Figure 2: 3.In figure 2. Assume the direction of the currents are correct but the polarity of the battery through which the current of 1A is flowing may or may not be correct. (a) The current I-1+2- 3A. (True, Palse) (b) For the loop on the left: -(3)(2) -e+ (1)(1) -0 which leads to e- -5 indicating that the assigned polarity of the battery is incorrect. (True, False) (c) the resistance r can be found from: -(3)(2) + 12 - 3r-0 leading to r 2. (True, False)

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Chapter17: Current And Resistance
Section: Chapter Questions
Problem 22P: The human body can exhibit a wide range of resistances to current depending on the path of the...
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12 V
Figure 2:
3.In figure 2. Assume the direction of the currents are correct but the polarity of the battery through which the current of 1A is flowing may
or may not be correct.
(a) The current I-1+2 = 3A.
(True, False)
(b) For the loop on the left: -(3)(2) -e+ (1)(1) - 0 which leads to e- -5 indicating that the assigned polarity of the battery is incorrect.
(True, False)
(c) the resistance r can be found from: -(3)(2) + 12 - 3r =0 leading to r= 2.
(True, False)
(d) If (a) and (c) are true then the power dissipated by the resistor r and power supplied by the 12V battery are is 18 Watts and 36 Watts
respectively.
(True, False)
(e) If (b) is true then the power dissipated by the 1n resistor, the 20 resistor and the power supplied to the 5V battery are 1 Watt, 12 Watt
and 5 Watta respectively.
(True, False)
(F) If (d) and (e) are true the power delivered by the 12V battery is +36Watts. The power dissipated by the resistors are 41Watts and
power stored in the 5V battery is +5Watts. This indicates that energy is not conserved.
(True, False)
(g) The potential of the point b is lower than the potential of point a by 6V: V, - Va - 6.
(True, False)
Transcribed Image Text:12 V Figure 2: 3.In figure 2. Assume the direction of the currents are correct but the polarity of the battery through which the current of 1A is flowing may or may not be correct. (a) The current I-1+2 = 3A. (True, False) (b) For the loop on the left: -(3)(2) -e+ (1)(1) - 0 which leads to e- -5 indicating that the assigned polarity of the battery is incorrect. (True, False) (c) the resistance r can be found from: -(3)(2) + 12 - 3r =0 leading to r= 2. (True, False) (d) If (a) and (c) are true then the power dissipated by the resistor r and power supplied by the 12V battery are is 18 Watts and 36 Watts respectively. (True, False) (e) If (b) is true then the power dissipated by the 1n resistor, the 20 resistor and the power supplied to the 5V battery are 1 Watt, 12 Watt and 5 Watta respectively. (True, False) (F) If (d) and (e) are true the power delivered by the 12V battery is +36Watts. The power dissipated by the resistors are 41Watts and power stored in the 5V battery is +5Watts. This indicates that energy is not conserved. (True, False) (g) The potential of the point b is lower than the potential of point a by 6V: V, - Va - 6. (True, False)
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