Homework Help is Here – Start Your Trial Now!
Science
Advanced Physics
12 = -aý cos p + aê sin o 13 = -l1 14 = -12 is â Bo everywhere.

12 = -aý cos p + aê sin o 13 = -l1 14 = -12 is â Bo everywhere.

icon
Related questions
Question
a rectangular wire loop carries current 1, nas height b, width a, and is centered on the origin. It can rotate about the z axis. For rotation angle o, the surface normal of the rectangle enclosed by the loop is î = âu cos o + ý sin ø, and the vectors representing the four sides of the loop are 1 = bê 12 = -aý cos o + aâ sin ø 13 = -l1 14 = -12 %3D The magnetic flux density is & Bo everywhere. (a) What is the magnetic flux through the loop as a function of ø? 12 = -aỹ cos o +aî sin ø 1 = bê 13 -1 în = âr cos o B = &B I4 = + ŷ sin ø -12 ntine i.
Transcribed Image Text:a rectangular wire loop carries current 1, nas height b, width a, and is centered on the origin. It can rotate about the z axis. For rotation angle o, the surface normal of the rectangle enclosed by the loop is î = âu cos o + ý sin ø, and the vectors representing the four sides of the loop are 1 = bê 12 = -aý cos o + aâ sin ø 13 = -l1 14 = -12 %3D The magnetic flux density is & Bo everywhere. (a) What is the magnetic flux through the loop as a function of ø? 12 = -aỹ cos o +aî sin ø 1 = bê 13 -1 în = âr cos o B = &B I4 = + ŷ sin ø -12 ntine i.
Expert Solution
Step 1

Given:

To find the magnetic flux through the loop is given as,

 

trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer