12-5 Let M = (kij), i, j = 1,..., n, define an operator on Cn. Then 1k is the sum of the eigenvalues of M, and det(k) is the product of the eigenvalues of M.
12-5 Let M = (kij), i, j = 1,..., n, define an operator on Cn. Then 1k is the sum of the eigenvalues of M, and det(k) is the product of the eigenvalues of M.
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter4: Eigenvalues And Eigenvectors
Section4.1: Introduction To Eigenvalues And Eigenvectors
Problem 36EQ: Consider again the matrix A in Exercise 35. Give conditions on a, b, c, and d such that A has two...
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![Let M = (kij), i, j = 1,...,n, define an operator on Cn. Then
kjj is the sum of the eigenvalues of M, and det(kij) is the product
of the eigenvalues of M.
12-5](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1e0012ff-a39a-4c1f-bd64-80877d91c93c%2Fe75fecbc-d69f-4961-b96e-fe4801d19491%2F57nncx8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Let M = (kij), i, j = 1,...,n, define an operator on Cn. Then
kjj is the sum of the eigenvalues of M, and det(kij) is the product
of the eigenvalues of M.
12-5
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