11:17 %10 Pb+2y=7.5+ 2 * 2.25=12 m RA/P 1.406 m V c√RS 55 1.406 * =2.06 m/s. 1000 Q=AV=16.875 * 2.06= 34.76 m³/s DOOOO Examples: Example 2: A triangular gutter with side slope at angle 60 has a depth 250 mm. If the discharge is 0.04 m3/s. Find the slope of the gutter bed? (c=50) 250 m Examples: Example 3: Design a trapezoidal channel of water having a velocity 0.6 m/s, channel side slope 1:1.5, flow rate 3 m3/s, c=65, hydraulic radius 10 m? Top width = b+2y- Δ Kay О ☐ K

Refer to Figure 7.24. The following data were collected during the field permeability measurement of a confined aquifer using a pumping test. Determine the hydraulic conductivity of the permeable layer. Use Eq. (7.49). Thickness of the aquifer, H = 4.5 m Piezometric level and radial distance of the first observation well: h1 = 2.9 m; r1 = 17.8 m Piezometric level and radial distance of the second observation well: h2 = 1.8 m; r2 = 8.1 m Rate of discharge from pumping, q = 0.5 m3/min

A sand has Gs = 2.66. Calculate the hydraulic gradient that will cause boiling for e = 0.35, 0.45, 0.55, 0.7, and 0.8.

For a soil, given: D10 = 0.08 mm D30 = 0.22 mm D60 = 0.41 mm Calculate the uniformity coefficient and the coefficient of gradation of the soil. 2.4 Repeat Problem 2.3 for the following: D10 = 0.24 mm D30 = 0.82 mm D60 = 1.81 mm