Related questions
Question
11-2) Please write very well written and legible. Write the answer regularly. I give a positive score to the regular answer.
Transcribed Image Text:(11.2) Show that, for an ideal gas,
R
=Y - 1
Cv
(11.37)
and
R
(11.38)
Cp
where Cy and C, are the heat capacities per mole.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by stepSolved in 3 steps
Knowledge Booster
Similar questions
- Part C Evaluate AVL at t = 1.0 ms, if L = 20 mH, Io = 50 mA, and T = 1.0 ms. Express your answer using two significant figures and include the appropriate units. ► View Available Hint(s) ▼ AVL = Value Submit HA Part D μÀ V Evaluate AVL at t = 3.0 ms, if L = 20 mH, Io = 50 mA, and T = 1.0 ms. Express your answer using two significant figures and include the appropriate units. ► View Available Hint(s) P Pearson ? www ?arrow_forwardCan i get some help pleasearrow_forwardS Can 6 PAR к Торс K Unit K In x K Moti = Cop K Unit S Spee S Topo S Math Micr eb.kamihq.com/web/viewer.html?source-filepicker&document_identifier=137VZR5BZOVSAIMOA55WU555_CvJ9NacO + 100 P e Interpreting Graphs Answer the questions following the graphs on each side Dietance va. Time 2 7 10 11 12 13 14 Time in soconds 1. From 1 second to 2 seconds, how fast is the object traveling. (Take the difference in distance and divide it by the time in between the 2 distances) 2. Is the object going as fast between 9 and 12 seconds as it is between 1 and 4 seconds? How can you tell? 3. What is the motion of the object between 4 and 6 seconds? acerarrow_forward
- ) if A = = 3i+4j +2K and B= -2i +6j +5k find A. B. (A .B änjö ) جد قيمة • Barrow_forwarda) Write down the metric and the inverse metric, and use the definitionrpµv = 1/2gpσ(δµgvσ + δvgµσ - δσgµv) = rpvµto reproduce the results written above for rθ ØØ and rØ θØ.arrow_forwardItem 12 (Figure 1)A neutral conducting sphere contains a spherical cavity. A point charge q is placed at the center of the cavity. Part A What is the total surface charge dint on the interior surface of the conductor? ► View Available Hint(s) VE ΑΣΦ gint = Submit ?arrow_forward
arrow_back_ios
arrow_forward_ios