
Elementary Geometry For College Students, 7e
7th Edition
ISBN: 9781337614085
Author: Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher: Cengage,
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Question
![**Instruction:**
11. Graph the linear inequality.
\[ y > \frac{3}{2}x + 5 \]
**Explanation:**
The image contains a Cartesian coordinate grid that ranges from -10 to 10 on both the x-axis and y-axis, with increments of 5. You are asked to graph the linear inequality \( y > \frac{3}{2}x + 5 \).
To graph this inequality:
1. **Graph the boundary line:** Start by graphing the line \( y = \frac{3}{2}x + 5 \). This line will be dashed since the inequality is 'greater than' (>) and does not include equality. This indicates that points on the line are not solutions to the inequality.
2. **Determine the region to shade:**
- Since the inequality is \( y > \frac{3}{2}x + 5 \), shade the entire region above the line. This represents all the points \((x, y)\) where the y-value is greater than \(\frac{3}{2}x + 5\).
By following these steps, you will have successfully graphed the linear inequality on the coordinate grid.](https://content.bartleby.com/qna-images/question/39f8eda8-4420-4bda-ab27-1b53a7c9ec36/eb7c8ac9-756a-4a33-ad57-a21e111b13d1/3a3z7qh_thumbnail.jpeg)
Transcribed Image Text:**Instruction:**
11. Graph the linear inequality.
\[ y > \frac{3}{2}x + 5 \]
**Explanation:**
The image contains a Cartesian coordinate grid that ranges from -10 to 10 on both the x-axis and y-axis, with increments of 5. You are asked to graph the linear inequality \( y > \frac{3}{2}x + 5 \).
To graph this inequality:
1. **Graph the boundary line:** Start by graphing the line \( y = \frac{3}{2}x + 5 \). This line will be dashed since the inequality is 'greater than' (>) and does not include equality. This indicates that points on the line are not solutions to the inequality.
2. **Determine the region to shade:**
- Since the inequality is \( y > \frac{3}{2}x + 5 \), shade the entire region above the line. This represents all the points \((x, y)\) where the y-value is greater than \(\frac{3}{2}x + 5\).
By following these steps, you will have successfully graphed the linear inequality on the coordinate grid.

Transcribed Image Text:For the relation \(\{(3,3), (2,6), (3,9), (4,12), (5,15)\}\):
a. Is this relation a function?
b. Find the domain of the relation.
c. Find the range of the relation.
Expert Solution

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Step 1
Disclaimer:
“Since you have asked multiple question, we will solve the first question for you. If you want any specific question to be solved then please specify the question number or post only that question.”
Concept:
Treat the sign as a sign when putting an inequality on a graph. Graph the equation as a dotted line if the inequality is either or. Graph the equation as a solid line if the inequality is either or. The x-y plane is split along this line into two regions: one that fulfils the inequality and the other that does not.
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Similar questions
- 6. Graph the linear inequality on the graph. m = y2x- 5arrow_forward25. Describe {x : x² + 2x < 3} as an interval. Hint: Plot y = x² + 2x – 3. SOLUTION The inequality x2 + 2x < 3 is equivalent to x2 + 2x – 3 < 0. The graph of y = x2 + 2x – 3 is shown below. From this graph, it follows that x² + 2x – 3 < 0 for –3 < x < 1. Thus, the set {x : x? + 2x < 3} is equivalent to the interval (-3, 1). y -x+ 2x – 3 12 10-arrow_forward1. Determine whether each ordered pair is a solution to the inequality y<3.x+2 ® (0,3) 6 (-3,-2) © (-2,0) @ (0,0) © (-1,4)arrow_forward
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