*11. Find Vs for the network of Fig. 7.84. 20 V 2.2 k2 Ipss = 4.5 mA Vps Vp =-5 V I ss = 6 mA Vp = -6 V 14 V 2.2 kQ 0.68 ka 0.39 k2 -4 V FIG. 7.83 FIG. 7.84 Problem 10. Problem 11.

Find V, in the network in Fig. 7 using source transformation. 6 kN 2 kN Rz$3 kN 6 V(+ · 4 kN Vo +)12 V Fig. 7

14. For the network of Fig. 7.86, Vp = 12 V. Determine: a. Ip. b. Vs and Vps- c. Vg and VGs. d. Vp.

2) (ch 4 #4 from Nise) Consider a single loop circuit consisting of a 5V de battery, a 1.8 ohm resistor, and a 0.79F capacitor. If the circuit is completed (think closing a switch) at t=0, find the capacitor voltage (in other words, find ve(t) as you did in DS1) in the network as a function of time. (1) Use KVL to find the equation of the circuit in terms of vc. (2) Take the Laplace transform of the equation. (3) Solve this equation for V (s) then take the inverse Laplace transform to get ve (t). Also find the time constant, rise time, and settling time for the capacitor voltage.