11- Let a filamentary current of 5 mA be directed from infinity to the origin on the positive z axis and then back out to infinity on the positive x axis. Find H at P(0, 1, 0): The Biot-Savart law is applied to the two wire segments using the following setup: Hp = -1² IdL x ag 4x R² Idza, = So 47 (2²+1)³/2 = -Idza, x (-za + ay) 47 (2²+1)3/2 + Idxa. 47 (x² + 1)³/2 (a, +a)= 0.40(a, + a) mA/m 47 So + Idxa, x (-xa, +ay) 4x (x²+1)3/2 I zax + [√²+16+ √²+16] 4x

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11-
Let a filamentary current of 5 mA be directed from infinity to the origin on the positive z axis and then
back out to infinity on the positive r axis. Find H at P(0, 1, 0): The Biot-Savart law is applied to the
two wire segments using the following setup:
Hp
IdL x ag
4x R²
I
-So
=
S
Idza,
47 (2²+1)3/2
-Idza, x (-za₂ + ay)
47 (2²+1)3/2
Idxa,
47 (x²+1)3/2
-1.⁰
+
-(ax +a)= 0.40(a, + a) mA/m
47
=
+ √°°
Ал
[₁
Idxa, x (-xa, + ay)
47 (x²+1)3/2
zax
{[%]
xa-
√x²+1/0
Transcribed Image Text:11- Let a filamentary current of 5 mA be directed from infinity to the origin on the positive z axis and then back out to infinity on the positive r axis. Find H at P(0, 1, 0): The Biot-Savart law is applied to the two wire segments using the following setup: Hp IdL x ag 4x R² I -So = S Idza, 47 (2²+1)3/2 -Idza, x (-za₂ + ay) 47 (2²+1)3/2 Idxa, 47 (x²+1)3/2 -1.⁰ + -(ax +a)= 0.40(a, + a) mA/m 47 = + √°° Ал [₁ Idxa, x (-xa, + ay) 47 (x²+1)3/2 zax {[%] xa- √x²+1/0
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