Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN: 9781259696527
Author: J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher: McGraw-Hill Education
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Tsuge and Matsuo studied precipitation of Mg(OH)2 by reacting aqueous solutions of MgCl2 and Ca(OH)2 in a 1-L MSMPR crystallizer operating at 450 rpm and 25oC. Crystal sizes were measured by a scanning-electron microscope (SEM) and analyzed by a digitizer. Crystal size was taken to be the maximum length. A plot of the crystal-size distribution is given in Figure for an assumed residence time of 5 minutes. Assuming that the number of crystals is proportional to exp(-L/Gτ), as in n=noexp(-L/Gτ), determine: (a) growth rate, (b) nucleation rate, and (c) predominant crystal size.

102
101
0.5
1.0
1.5
2.0
Crystal size, um
Number of crystals
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Transcribed Image Text:102 101 0.5 1.0 1.5 2.0 Crystal size, um Number of crystals
Expert Solution
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Step 1

Magnesium hydroxide is precipitated by reacting of aqueous solution of MgCl2 and Ca(OH)2 in a 1-L MSMPR crystallizer.

The operating conditions of crystallizer are given as:

Temperature = 25 0C

Impeller speed = 450 rpm

The crystal size distribution is given in the figure.

Residence time = 5 min

Number of crystal is equal to,

n = n0e(-L/Gτ)

Step 2

(a)

 

Growth rate of the crystal is calculated as follows:

 

The equation to calculate the number of crystal is given as,

Chemical Engineering homework question answer, step 2, image 1

Where,

 

n represents the number of crystal.

n0 represents the proportionality constant.

L represents the length.

G represents the growth rate.

Ττ represents the residence time

 

The proportionality constant is also equal to,

Chemical Engineering homework question answer, step 2, image 2

Where,

B0 represents the nucleation rate.

The equation (1) becomes,

Chemical Engineering homework question answer, step 2, image 3

Take the log on the both sides of the equation (2)

Chemical Engineering homework question answer, step 2, image 4

 

Step 3

Equation (3) represents a straight equation (y = mx +c)

Where,

y = n

m= G/2.303τ

x = l

c = log B0/G

The values of unknowns are calculated as follows:

Take two values (extreme points) of number of crystals and corresponding values of the crystal size from the graph given in the question.

For n = 90

L = 0.6

For n = 3

L = 1.3

The residence time = 5 min

Plugin the values in equation (3)

Chemical Engineering homework question answer, step 3, image 1

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