100 mm (a)

8. What force P must be applied to the weightless wedges shown in the figure to start them under the 1200 lb block. The angle of friction for all contact surfaces is 15°. 1200 lb P P 20° 20° Answer: P = 580.8940 lb

Using τall = 71 MPa and G = 27 GPa, determine for each of the aluminum bars shown the largest torque T that can be applied and the corresponding angle of twist at end B. Refer to Table 3.1.       The largest torque that can be applied at end B of bar a is  N·m and the corresponding angle of twist is  °.   The largest torque that can be applied at end B of bar b is  N·m and the corresponding angle of twist is  °.

A bar of length L tapers uniformly from diameter 1.1 D at one end to 0.9 D at the other end. The elongation due to axial pull is computed using mean diameter D. What is the approximate error in computed elongation? [IES-2004] (a) 10% (b) 5% (c) 1% (d) 0.5% The stretch in a steel rod of circular section, having a length 'l' subjected to a tensile load' P' and tapering uniformly from a diameter di at one end to a diameter d₂ at the other end, is given [IES-1995] Pl pl.л 4 pl (b) 4Ed,d₂ Ed,d₂ Edd₂ (a) (c) pl.л 4 Ed,d₂ (d)

Q1/ The weights of the various components of the truck are shown. Replace this system of forces by an equivalent resultant force and specify its location measured from B? Ans: R=- 10750 lb, d= 13.7 ft 3500 lb B 5500 lb) A 1750 lb tont -14 ft- 3 ft 2 ft ...

A 10-lb force is pushing the 40-lb block as shown. The incline angle of the plane is α=40º . The coefficient of static friction between the block and the incline is μs = 0.75 and the coefficient of kinetic friction is μk = 0.65. Will the block slide on the plane? If it does, will it slide up or down the plane? What is the friction force between the block and the plane?