What is the IR and HNMRAndCNMR and mass N4000100BO6040th SpectrumSof941030004013C NMR Spectrum(566 MCDO), soon)proton coupled200H NMR Spectrum000 , COC, stor8802000v (em¹)107/1091201000m/e160M166/186/1901601200800Mass SpectrumC₂H4Br₂200 240 200120solvent804Problem 5C-30021No significant UVabsorption above 220 nm340208 (ppm)TMS08 (ppm

Please find your solution below : Spectroscopy is the study of absorption or emission of radiation…

100 BO 40 40 13C NMR Spectrum 60, COO, MA 200 H NMR Spectrum 10 3000 94 BO 8 2000 v (em¹) 107/109 120 1000 160 M 166/106/190 160 1200 800 Mass Spectrum 120 6 200 240 200 C₂H4Br₂ solvent 80 4 st Problem Bro 300 G No significant UV absorption above 220 nm 3 40 0 8 (ppm) TMS 0 & (ppm

100 BO 40 40 13C NMR Spectrum 60, COO, MA 200 H NMR Spectrum 10 3000 94 BO 8 2000 v (em¹) 107/109 120 1000 160 M 166/106/190 160 1200 800 Mass Spectrum 120 6 200 240 200 C₂H4Br₂ solvent 80 4 st Problem Bro 300 G No significant UV absorption above 220 nm 3 40 0 8 (ppm) TMS 0 & (ppm

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

What is the IR and HNMRAndCNMR and mass

N
4000
100
BO
60
40
th Spectrum
Sof
94
10
3000
40
13C NMR Spectrum
(566 MCDO), soon)
proton coupled
200
H NMR Spectrum
000 , COC, stor
8
80
2000
v (em¹)
107/109
120
1000
m/e
160
M
166/186/190
160
1200
800
Mass Spectrum
C₂H4Br₂
200 240 200
120
solvent
80
4
Problem 5
C-300
21
No significant UV
absorption above 220 nm
3
40
2
0
8 (ppm)
TMS
0
8 (ppm

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