College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- 3. The gravitational acceleration at Earth's surface (ga) is about 10 m/s? and ge = GM/R2. What is g, at the surface of a planet with 2X Earth's mass and 3X Earth's radius?arrow_forward1. using Newton’s Law of Universal Gravitation and some kinematics calculation we can calculate the mass of the planet. For this, use this equation below: ?planet =(9.340×1024)×(vmax)×(Pstar)1/3×(Mstar)2/3 Given: - vmax = 1.5 m/s - Pstar = 3.5 days - Mstar = 1.148 Msun, where Msun = 1.98847×1030 kg. This calculation is not shown.arrow_forwardDetermine the ratio of Earth's gravitational force exerted on an 80-kg person when at Earth's surface and when 1100 km above Earth's surface. The radius of Earth is 6370 km. FE on P,surface FE on Ph 195] ΑΣΦ ?arrow_forward
- 6. A synchronous orbit is an orbit about a planet's equator that always remains above the same spot of the planet because the synchronous orbit matches the planet's rotational period. The pilot of the Mars spacecraft (which was named Cheetah 1 and had a 9556 kg mass) asked Tarzan to calculate the altitude of a synchronous orbit so they could remain over a particular geological feature on the Martian equator. Calculate the altitude above the Martian equator using the data above and Johannes Kepler's genius.arrow_forwardc) Draw the expected tidal record (tidal height relative to mean sea level versus time) for the month illustrated above. Annotate the four points of time represented in the figure below. How are these tides called? Moon Moon Sun Sun Moon Moon Sun Sunarrow_forwardA planet and moon pictured above have identical densities. Identify the magnitude of the value that is identical to both cosmic bodies assuming that the only force they experience is their gravitational attraction for each other. O A. Kinetic energy O B. Velocity O C. Acceleration O D. Displacement from the center of mass O E. Gravitational forcearrow_forward
- 1. On a planet whose radius is 1.5 × 107 m, the acceleration due to gravity is 20 m/s². An astronaut with a mass of 60 kg is standing on its surface.arrow_forwardAccording to Lunar Laser Ranging experiments the average distance LM from the Earth to the Moon is approximately 3.85 × 10° km. The Moon orbits the Earth and completes one revolution in approximately 27.5 days (a sidereal month). How can the mass of the Earth be calculated using the information above? Select the correct statements. Select one or more: O a. Use Newton's third law. O b. Use Newton's first law. c. Use Coulombs law. O d. Use Newton's second law.arrow_forwardLeave the moon's amplitude (semi-major axis) constant. How does the changing of the moon's orbital period change the calculated value of the planet's mass? a. Increasing the orbital period results in a higher calculated value for the mass of the planet. Decreasing the orbital period results in a lower calculated value for the mass of the planet. b. Increasing the orbital period results in a lower calculated value for the mass of the planet. Decreasing the orbital period results in a higher calculated value for the mass of the planet. c. Increasing the orbital period results in a higher calculates value for the mass of the planet. Decreasing the orbital period results in a higher calculated value for the mass of the planet.arrow_forward
- Part A The value of Gmdre", where me is the mass of the earth, r, is the radius of the earth, and G is the universal gravitational constant is (enter your answer with three significant figures) ΑΣΦ IXI X•10n -11 6.67 101 m/? Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remainingarrow_forward3. The gravitational acceleration at Earth's surface (ge) is about 10 m/s? and ge = GM/R?. What is gp at the surface of a planet with 2X Earth's mass and 3X Earth's radius?arrow_forward
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