10. Suppose the interference pattern shown in the figure below is produced by monochromatic light passing through a diffraction grating, that has 180 lines/mm, and onto a screen 1.80 m away. What is the wavelength of light if the distance between the dashed lines is 37.8 cm? 20 91150 911 nm 16 corto ceil6 ceiló ceilo ceil 16 16 cc116 co cil6 ceil6 ceil

10. Suppose the interference pattern shown in the figure below is produced by monochromatic light passing through a diffraction grating, that has 180 lines/mm, and onto a screen 1.80 m away. What is the wavelength of light if the distance between the dashed lines is 37.8 cm? 20 91150 911 nm 16 corto ceil6 ceiló ceilo ceil 16 16 cc116 co cil6 ceil6 ceil

University Physics Volume 3

17th Edition

ISBN:9781938168185

Author:William Moebs, Jeff Sanny

Publisher:William Moebs, Jeff Sanny

Chapter4: Diffraction

Section: Chapter Questions

Problem 90AP: A monochromatic light of unknown wavelength is incident on a slit of width 20 m. A diffraction...

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In Figure P36.10 (not to scale), let L = 1.20 m and d = 0.120 mm and assume the slit system is illuminated with monochromatic 500-nm light. Calculate the phase difference between the two wave fronts arriving at P when (a) = 0.500 and (b) y = 5.00 mm. (c) What is the value of for which the phase difference is 0.333 rad? (d) What is the value of for which the path difference is /4? Figure P36.10
In Figure P27.7 (not to scale), let L = 1.20 m and d = 0.120 mm and assume the slit system is illuminated with monochromatic 500-nm light. Calculate the phase difference between the two wave fronts arriving at P when (a) = 0.500 and (b) y = 5.00 mm. (c) What is the value of for which the phase difference is 0.333 rad? (d) What is the value of for which the path difference is /4?
A diffraction pattern is produced on a screen 1.40 m from a single slit, using monochromatic light of wavelength 5.00 102 nm. The distance from the center of the central maximum to the first-order maximum is 3.00 mm. Calculate the slit width. Hint: Assume that the first-order maximum is halfway between the first- and second-order minima.
White light is incident on a diffraction grating with 475 lines/mm. (a) Calculate the angle r2 to the second-order maximum for a wavelength of 675 nm. (b) Calculate the wavelength of light with a third-order maximum at the same angle r2.
A monochromatic light of unknown wavelength is incident on a slit of width 20 m. A diffraction pattern is seen at a screen 2.5 m away where the central maximum is spread over a distance of 10.0 cm. Find the wavelength.
The intensity on the screen at a certain point in a double- slit interference pattern is 64.0% of the maximum value. (a) What minimum phase difference (in radians) between sources produces this result? (b) Express this phase difference as a path difference for 486.1-nm light.
In Figure 37.7, show mathematically how many interference maxima are enclosed by the central diffraction maximum in the pattern. Notice that the diagram is generated by using 650-nm light to illuminate two 3.0-m slits separated by 18 m. Figure 37.7 The combined effects of two-slit and single-slit interference. This pattern is produced when 650-nm light waves pass through two 3.0-m slits that are 18 m apart.
Monochromatic light of wavelength 620 nm passes through a very narrow slit S and then strikes a screen in which are two parallel slits. S1 and S2, as shown in Figure P37.75. Slit S1 is directly in line with S and at a distance of L = 1.20 in away from S, whereas S2, is displaced a distance d to one side. The light is detected at point /Jon a second screen, equidistant from S1 and S2. When either slit S1 or S2 is open, equal light intensities are measured at point P. When both slits are open, the intensity is three times larger. Find the minimum possible value for the slit separation d.
Show that the distribution of intensity in a double-slit pattern is given by Equation 36.9. Begin by assuming that the total magnitude of the electric field at point P on the screen in Figure 36.4 is the superposition of two waves, with electric field magnitudes E1=E0sintE2=E0sin(t+) The phase angle in in E2 is due to the extra path length traveled by the lower beam in Figure 36.4. Recall from Equation 33.27 that the intensity of light is proportional to the square of the amplitude of the electric field. In addition, the apparent intensity of the pattern is the time-averaged intensity of the electromagnetic wave. You will need to evaluate the integral of the square of the sine function over one period. Refer to Figure 32.5 for an easy way to perform this evaluation. You will also need the trigonometric identity sinA+sinB=2sin(A+B2)cos(AB2)
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What is the spacing between structures in a feather that acts as a reflection grating, given that they produce a first-order maximum for 525-nm light at a 30.0° angle?