10. K= { a | k=n² and n2l }
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- if L1={ab,b} L2={abb,bb} then L1L2= * O {ababb,abbb,abbab,bbab} O {ab,b,abb,bb} O {ababb,abbb,babb,bbb} O {abbab,abbb,bbab,bbb}Match the C-function on the left to the Intel assemble function on the right. W: cmpl $4 movl %edi , %edi jmp .L4(,%rdi,8) %edi .L3: movl $17, %eax ret .15: movl $3, %eax int A ( int x , int y) { int a ; if ( x == 0 ) else i f ( x == 1 ) a = 3 ; else i f ( x == 2 ) a = 2 0 ; else i f ( x == 3 ) a = 2 ; else i f ( x == 4 ) a = 1 ; ret .L6: a = 17; movl $20, %eax ret .L7: movl $2, %eax ret else a = 0; .L8: return a ; movl $1, %eax .L2: ret . section .rodata . L4: .quad .L3 .quad .L5 .quad .L6 .quad .L7 .quad .L8 X: testl %edi, %edi je cmpl je cmpl je стр1 je cmpl .L16 $1, %edi .L17 $2, %edi .L18 $3, %edi int B (int x, int y) { int a; switch (x) { .L19 $4, %edi %al movzbl %al, %eax case 0: a = 17; break; sete break; case 1: a = 3; case 2: a = 20; break; case 3: a = 2; break; case 4: a = 1; a = 0; } return a; ret .L16: break; movl $17, %eax ret .L17: movl $3, %eax } ret .L18: movl $20, %eax ret .L19: movl ret $2, %eaxGiven the following definitions: U={a,b,c, d, e, f, g} A={a, c, e, g} B={a,b,c,d} find A n B
- Write a function that displays an n-by-n matrix using the following header: void printMatrix(int n)Each element is 0 or 1, which is generated randomly. Write a test program that prompts the user to enter n and displays an n-by-n matrix.* .gcd(91, 287) =gcd(91, 14) yes NoK Lold T T=T+(K-2)*L T=T- 10 T=0 T=T-10 K= 4, 8, 2 L=4, 3, -1 T=T+{K-2)*L
- Count consecutive summers def count_consecutive_summers(n): Like a majestic wild horse waiting for the rugged hero to tame it, positive integers can be broken down as sums of consecutive positive integers in various ways. For example, the integer 42 often used as placeholder in this kind of discussions can be broken down into such a sum in four different ways: (a) 3 + 4 + 5 + 6 + 7 + 8 + 9, (b) 9 + 10 + 11 + 12, (c) 13 + 14 + 15 and (d) 42. As the last solution (d) shows, any positive integer can always be trivially expressed as a singleton sum that consists of that integer alone. Given a positive integer n, determine how many different ways it can be expressed as a sum of consecutive positive integers, and return that count. The number of ways that a positive integer n can be represented as a sum of consecutive integers is called its politeness, and can also be computed by tallying up the number of odd divisors of that number. However, note that the linked Wikipedia de0inition…Example: Enter an integer = 75 Smallest divisor is = 3Each of two players rolls a dice and whoever rolls the highest number (between 1 and 6 inclusive) gets 4 points, and if it is a draw, both players get 2 points. The player with the highest number of points after 10 rounds of the game is the winner (or the game could be drawn). The following arrays contain the results of dice rolls of each of two players in 10 consecutive rounds of the game.player1=[3, 2, 5, 6, 2, 5, 1, 6, 4, 5]player2=[4, 2, 4, 3, 6, 5, 3, 2, 4, 1] Write a MATLAB program that computes the running total points of each player and displays one of the following messages (whichever applies) after each round n for n = 1, 2, . . . , 10:Player 1 is leadingPlayer 2 is leadingIt is a tie [Hint: You should use an if construct.]Also, at the end of your program, use the find command to identify (and display) the rounds in which dice rolls were the same for the two players, and use the length command to compute (and display) the number of such rounds. Include appropriate headings in…