10. Given the pH of 1.5 M chloroacetic acid, CH2CICOOH solution is 1.96. a. Write an equation to show the dissociation of CH2CICOOH in water. b. Calculate the Ka of the acid. c. Calculate the pKb of its conjugate base. d. Which is a stronger base, acetate ion or the conjugate base of CH2CICOOH? (Ka of acetic acid, CH3COOH = 1.8 x 10-5) %3D

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter14: Acids And Bases
Section: Chapter Questions
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10. Given the pH of 1.5 M chloroacetic acid, CH2CICOOH solution is 1.96.
a. Write an equation to show the dissociation of CH2CICOOH in water.
b. Calculate the Ka of the acid.
c. Calculate the pKb of its conjugate base.
d. Which is a stronger base, acetate ion or the conjugate base of CH2CICOOH?
(Ka of acetic acid, CH3COOH = 1.8 x 105)
Transcribed Image Text:10. Given the pH of 1.5 M chloroacetic acid, CH2CICOOH solution is 1.96. a. Write an equation to show the dissociation of CH2CICOOH in water. b. Calculate the Ka of the acid. c. Calculate the pKb of its conjugate base. d. Which is a stronger base, acetate ion or the conjugate base of CH2CICOOH? (Ka of acetic acid, CH3COOH = 1.8 x 105)
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