10. Consider a banked wet curved roadway, where there is a coefficient of static friction of 0.30 and a coefficient of kinetic friction of 0.25 between the tires and the roadway. The radius of the curve is R = 50 m. If the banking angle is ß = 25° a) What is the maximum speed the automobile can have before sliding up the banking? b) What is the minimum speed the automobile can have before sliding down the banking?

10. Consider a banked wet curved roadway, where there is a coefficient of static friction of 0.30 and a coefficient of kinetic friction of 0.25 between the tires and the roadway. The radius of the curve is R = 50 m. If the banking angle is ß = 25° a) What is the maximum speed the automobile can have before sliding up the banking? b) What is the minimum speed the automobile can have before sliding down the banking?

Name: Consider a banked wet curved roadway, where there is a coefficient of
Uploaded: 2024-03-20T06:57:57.000Z
Channel: Bartleby
Description: Consider a banked wet curved roadway, where there is a coefficient of static friction of 0.30 and a coefficient of kinetic friction of 0.25 between the tires and the roadway. The radius of the curve is R = 50 m. If the banking angle is ? = 25°a) What

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter6: Applications Of Newton’s Laws Of Motion

Section: Chapter Questions

Problem 46PQ

See similar textbooks

Similar questions

Modem roller coasters have vertical loops like the one shown here. The radius of curvature is smaller at the top than on the sides so that the downward centripetal acceleration at the top will be greater than the acceleration due to gravity, keeping the passengers pressed firmly into their seats. (a) What is the speed of the roller coaster at the top of the loop if the radius of curvature there is 15.0 m and the downward acceleration of the car is 1.50 g ? (b) How high above the top of the loop must the roller coaster start from rest, assuming negligible friction? (c) If it actually starts 5.00 m higher than your answer to (b), how much energy did it lose to friction? Its mass is 1.50103kg .
A banked highway is designed for traffic moving at 90.0 km/h. The radius of the curve is 310 m. What is the angle of banking of the highway?
A number of amusement parks have rides that make loops like the one shown in Figure 6.33. For safety, the cars are attached to the rails in such a way cannot fall off. If the car goes over the top at just the right speed, gravity alone will supply the centripetal force. What other force acts and what is its direction if: (a) The car goes over the top at faster than this speed? (b) The car goes this speed? Figure 6.33 Amusement rides with a vertical loop are an example of a form of curved motion.
If a car takes a banked curve at less than the ideal speed, friction is needed to keep It from sliding toward the inside of the curve (a problem on icy mountain roads). (a) Calculate the ideal speed to take a 100.0 m radius curve banked at 15.0. (b) What is the minimum coefficient of friction needed for a frightened driver to take the same curve at 20.0 km/h?
1. What coefficient of friction do cars need on a flat curve? (a) Calculate the centripetal force exerted on a 950 kg car that negotiates a 450 m radius curve at m 20.0 . S Enter to 3 significant figures F = 844.44 N (b) Assuming an unbanked curve, find the minimum static coefficient of friction between the tires and the road, static friction being the reason that keeps the car from slipping (see figure below). W Free-body diagram f N 13 W f = Fc Caption: This car on level ground is moving away and turning to the left. The centripetal force causing the car to turn in a circular path is due to friction between the tires and the road. A minimum coefficient of friction is needed, or the car will move in a larger-radius curve and leave the roadway. Enter to 3 significant figures Hs= 0.899 √
15 . A car makes a 50-m-radius turn on a flat road with no banking. The car speeds up until a book on the floor overcomes friction and starts to slide outward. If the coefficient of static friction is 0.45, what was the speed of the car when the book began to slide?
16. A banked circular road is designed for traffic moving at 60.0 km/h, radius of the curve is 200.0 m. Draw FBD and find angle. It is a stormy night and cars are traveling at 40.0 km/h. What is minimum coefficient of friction that will allow cars to negotiate turn without sliding?
If the curve on the road has a bank angle of 18 degrees and the radius of curvature is 225m. a) what is the maximum speed you can go if the coefficient of friction between the tires and the road is 0.3? Your car is 1500kg. b)What is the minimum speed you can go without sliding?
11. A crate of eggs is located in the middle of the flatbed W of a pickup truck as the truck negotiates a curve in the flat road. The curve may be regarded as an arc of a circle of radius 35.0 m. If the coefficient of static fric- tion between crate and truck is 0.600, how fast can the truck be moving without the crate sliding?
If a car takes a banked curve at less than the ideal speed, friction is needed to keep it from sliding toward the inside of the curve (a real problem on icy mountain roads). A.)Calculate the ideal speed in (m/s) to take a 80 m radius curve banked at 15° B.)What is the minimum coefficient of friction needed for a frightened driver to take the same curve at 20.0 km/h?
A curve of 80m radius is banked at 7.5 degrees to the horizontal. A car of mass 1.5 tonnes has to negotiate this bend. The coefficient of friction between the tyres and the road is 0.8.Calculate: 1. The side pressure on the tyres when the car is stationary in the bend.2.The speed at which this car would experience no side pressure on tis tyres when rounding the bend.3. The speed at which this car would be on the point of skidding in this bend.
1) m, = 5 kg m, = 10 kg 0 = 30° Hx = 0.3 m, HK m, Two masses are connected via a tensile string over a massless, frictionless pulley. The system is released from rest. Calculate the speed of the blocks after 2 seconds.