Related questions
Question
Transcribed Image Text:10. A diverging lens with a focal length of -48.0 cm forms a virtual image 8.00 mm tall, 17.0
cm to the right of the lens. (a) Determine the position and size of the object. Is the image
upright or inverted? Are the object and image on the same side or opposite sides of the
lens? (b) Draw a principal-ray diagram for this situation.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by stepSolved in 2 steps with 2 images
Knowledge Booster
Similar questions
- 6. A thin converging lens of focal length f =+12.0 cm is separated from a thin diverging lens by a distance d = 24.0 cm . The focal length of the second lens is f, =-48.0 cm. An object with height y = 4.20 cm is placed on the optical axis at p, =18.0 cm in front of the first lens. Pay attention to +/- signs. What is the location of the image produced by the first lens alone, i ? а. b. What is the lateral magnification m , produced by the first lens alone? с. Where is the final image of the two lens system located relative to the second lens (i.e. what is i,)? d. What is the total magnification of the two lens system, M ? What is the height of the final image, y, ? е. R/V? - Is the final image real or virtual? g. I/NI? - Is the final image inverted or not inverted (relative to the object in front of the first lens)? f.arrow_forwardA contact lens is made of plastic with an index of refraction 1.50. The lens has an outer radius of curvature of + 1.65 cm and an inner radius of curvature of + 5.85 cm. What is its focal length? TTTT Paragraph Arial 3 (12pt) E - E - T- 回i 公 T T, Bullet List O f. Mashups- HTML CSSarrow_forward#1e.. length of -6.0 [cm]. Find (a) the image distance and (b) the magnification. An object is placed 16 [cm] in front of a diverging lens with a focalarrow_forward
- Can you help me calculate the height. I kept getting it wrong.arrow_forwardCreate a ray diagram for eyeglasses that contain a diverging lens. Assume you are looking at a 2 cm tall object that is 4 cm from the lens. The focal length is 3 cm. What type of vision are they used to correct? Give both names. How do they do this? Explain.arrow_forwardPlease don't provide handwritten solution.... A diverging lens with f = -37.5 cm is placed 15.0 cm behind a converging lens with f = 21.0 cm .Where will an object at infinity be focused? Determine the image distance from the second lens. Follow the sign conventions.arrow_forward
- 6. A 2.0 cm tall object is 15 cm in front of a converging lens that has a 20 cm focallength.(a) Use ray tracing to find the position and height of the image. To do this accurately, use a ruler or a paper with a grid. Determine the image distance and imageheight by making measurements on your diagram.(b) Calculate the image position and height. Compare with your ray-tracing answers in part a.arrow_forward3. A cell phone has a fixed focal length lens of f = 3.85 mm = 0.00385 m and can take pictures over a range of distances from S. = 0.5 m to S,= infinity. Over what range of distances (S₁) does the lens in the cellphone have to move to focus an image at these two extremes in object distance?arrow_forwardA converging lens has a focal length of 20.0 cm. Construct accurate ray diagrams for object distances of (i) 60.0 cm and (ii) 6.67 cm. (a) From your ray diagrams, determine the location of each image. Image (i) distance = Image (ii) distance =arrow_forward
arrow_back_ios
arrow_forward_ios