10 Ω 2002 is 20 lb va 12 3 Va E ≤502 13 10 V
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Use mesh technique to calculate the mesh currents of the following circuit.
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- Fill in all the missing values. Refer to the formulas that follow. Resistance Capacitance Time constant Total time 150 k 100 F 350 k 35 s 350 pF 10 s 0.05 F 1.2 M 0.47 F 12F 0.05 s 86 k 1.5 s 120 k 470 pF 250 nF 100 ms 8 F 150 s 100 k 150 ms 33 k 4 F =RCR=CC=R Totaltime=5Consider the circuit below. The frequency of oscillation is: www OF R₂ 1,0 ΚΩ C₁ 0.015 μF R₁ 1.0 ΚΩ 11 L Q₁ 2N5458 C₂ 0.015 μF 10.6 kHz 1.94 kHz 19.4 kHz 15.9 kHz www R₁ 10 ΚΩ R3 820 02 ww R₁ 10 ΚΩ ovour D₁ IN914 C3 1.0 μεWhat is the total equivalent (total) inductance Lr of this circuit? 000 30mH L2 R 000 60mH 1 kQ 10 V L3 100mH 000 500mH 43 mH 720 mH O 173 mH o 日 点四RUA 36% DE 40°F PriSc Impr. Écr. F12 F10 F11 F7 F8 F9 F4 F5 F6 * & 3 0 1/4 1/2 4. 5 6. 7 8 2 R Y K L
- Discussion For the circuit below complete the table R 5 Ω 10 V 60 Hz 100 μF R Total 10+j0 10 0° Volts 68.623m +j364.06m Amps 370.5m Z 79.325° 5+ j0 0- j26.5258 5 - j26.5258 Ohms 520° 26.5258 -90° 26.993 Z-79.325°Draw a small signal AC equivalent circuit. Assume V=0 +20V Rc1 2k2 Cc 10µF R1 100k2 R Rc2 3k2 2k2 Vo 4µF Zo B = 100 Rs 1k2 R2 20k2 RE 5k2 CE 70µF VsDiscussion For the circuit below complete the table R 5 Ω 10 V 60 Hz 100 μF R Total 10+j0 10 0° Volts 68.623m+ j364.06m Amps 370.5m Z 79.325° 5+ j0 0- j26.5258 5 - j26.5258 Ohms 52 0° 26.5258 Z-90° 26.993 Z-79.325° N
- Find: Ib, Ic, Vce, Vb, Vc, Vrb Vre, & Vrc Note: show your solutions no solution means wrong answers. C2 HE 1000μF Rb 560 ΚΩ VCC 12V Rc 2kQ Q1 C1 요 HE 1000μF 2SC1815 R1 2000Q/ What is the value of Rtoti ? 12, 472 Ry {150n R2 472 300 R6 300L R3 150 nISMA 3K un 3K un + Vs 7mH 3√1₂ Im mn SmH -+ 20 V t IMF Vc What is Vs. iz Ve at steady-state?
- Discussion For the circuit below complete the table R 5Ω 10 V 60 Hz 100 µF R C Total 10 + j0 V Volts 10 Z0° 68.623m + j364.06m Amps 370.5m Z 79.325° 5+ j0 52 0° 5 - j26.5258 26.993 Z-79.325° 0 - j26.5258 Ohms 26.5258 Z-90°Find the Ceg for the circuit given below: C C C eq C C O 10 O 2.5C O 20 O 1.5Cfor the circuit shown below If v_in=5 sin2m10t then corner frequency will be ......Hz 1 UF 2 k Ohm 1 k Ohim 050 060 070 080 vin