10 V vs t V vs Number of turns 100 60 n 80 1 time (s)? 3 3 1 V vs angle V vs r 0.5 1 50 100 150 200 -0.5 0.2 0.4 0.6 -1 O (degrees) r(m) nBr2 sin 0 V = nr² cos 0 V = t nr? sin 0 V = nBr2 cos 0 V = V = ntr² cos 0 nr V = 40 20 (^)A O (A)A

Two parallel metal plates separated by 20 cm are connected across a 12 V potential difference. An electron is released from rest at a location 10 cm from the negative plate. When the electron arrives at a distance 5 cm from the positive plate, how much kinetic energy has the electron gained? Hint: First you will need to calculate the value of the electric field between the plates, then the potential difference between the initial and final positions. Now use the Work–Energy Theorem. Standard units!

How would you rearrange that equation for m_0

A negatively charged particle of mass 4.30 x 10-19 kg is moving with a speed of 35.0 m/s when it enters the region between two parallel capacitor plates. The initial velocity of the charge is parallel to the plate surfaces and in the positive x-direction. The plates are square with a side of 1.00 cm, and the voltage across the plates is 2.50 V. If the particle is initially 1.00 mm from both plates and it just barely clears the positive plate after traveling 1.00 cm through the region between the plates, how many excess electrons are on the particle? Ignore gravitational and edge effects. 35.0 m/s 2.00 mm 1.00 cm Numeric Response