10) The velocity of an object on the time interval [0, 5] is given in the graph below. On what interval(s) is the object's position decreasing? 31 vit) 1

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**Title: Analyzing Velocity and Position Decrease**

**Question**: The velocity of an object on the time interval [0, 5] is given in the graph below. On what interval(s) is the object's position decreasing?

**Graph Description**:
The graph plots velocity \( v(t) \) against time \( t \) from 0 to 5.

- The horizontal axis represents time \( t \).
- The vertical axis represents velocity \( v(t) \).

**Graph Details**:
- **From \( t = 0 \) to \( t = 1 \)**: The velocity decreases linearly from 2 to 0.
- **From \( t = 1 \) to \( t = 3 \)**: The velocity continues to decrease, becoming negative, from 0 to -2.
- **From \( t = 3 \) to \( t = 4 \)**: The velocity is constant at -2.
- **From \( t = 4 \) to \( t = 5 \)**: The velocity increases from -2 to 0.

**Analysis**:
The object's position is decreasing where the velocity is negative.

- **Interval of Decrease**: From \( t = 1 \) to \( t = 4 \) (when velocity is negative).

The object's position decreases during the interval where the velocity remains below zero, specifically from \( t = 1 \) to \( t = 4 \) in this scenario.
Transcribed Image Text:**Title: Analyzing Velocity and Position Decrease** **Question**: The velocity of an object on the time interval [0, 5] is given in the graph below. On what interval(s) is the object's position decreasing? **Graph Description**: The graph plots velocity \( v(t) \) against time \( t \) from 0 to 5. - The horizontal axis represents time \( t \). - The vertical axis represents velocity \( v(t) \). **Graph Details**: - **From \( t = 0 \) to \( t = 1 \)**: The velocity decreases linearly from 2 to 0. - **From \( t = 1 \) to \( t = 3 \)**: The velocity continues to decrease, becoming negative, from 0 to -2. - **From \( t = 3 \) to \( t = 4 \)**: The velocity is constant at -2. - **From \( t = 4 \) to \( t = 5 \)**: The velocity increases from -2 to 0. **Analysis**: The object's position is decreasing where the velocity is negative. - **Interval of Decrease**: From \( t = 1 \) to \( t = 4 \) (when velocity is negative). The object's position decreases during the interval where the velocity remains below zero, specifically from \( t = 1 \) to \( t = 4 \) in this scenario.
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