10 mL of 1.8 M acetic acid (CH3COOH) is titrated with 1.0 M sodium hydroxide (NaOH). The titration curve is shown. What is the approximate pK₁? pK₂ = 0.5 12 108 fraction converted: 0.5 吉 6 4 2 0 At the pK₁, what fraction of the carboxyl group will have been converted to COO¯? Express your answer as a decimal, not a percent. 0 5 10 15 Volume of base (mL) 20 25
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What is the approximate p?apa?
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The second part is correct.
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- A 100 mL solution of 0.1 M glycine at pH 1.72 was titrated with 2 M LIOH. The pH was monitored and the result were plotted as shown in the graph. The key points of the titration are designated as I to V. Identify the key point in the titration corresponding to the pH at which the carboxyl group is half deprotonated. 12 JL30 (V) 9.60 (IV) 8 5.97 pH 6 2.34 CII) 2 (I) 0.5 1.0 1.5 2.0 OH (equivalents) IV O Il and IV NextQuinine ( C20 H24 N2 O2) is the most important alkaloid derived from cinchona bark. It is used as an antimalarial drug. For quinine, pK, = 5.1 and pK, = 9.7 ( pKp = – log Kp). Only 1 g quinine will dissolve in 1920.0 mL of solution. Calculate the pH of a saturated aqueous solution of quinine. Consider only the reaction | Q+ H2O= QH+ + OH- described by pK, where Q = quinine. pH =80mL of a 0.3M solution of hexapeptide Leu-His-Cys-Glu-Asn-Arg is adjusted to pH=pI. The solution is then titrated with 0.2M HCL to a final pH of 2.1. Sketch the titration curve, labelling the pH and volume axes. Indicate the volume of HCL needed to reach relevant pKa value and equivalence point(s)z Relevant pKa values are: 2.1, 4.3, 6.0, 8.3, 9.8, and 12.5.
- 80mL of a 0.3M solution of hexapeptide Leu-His-Cys-Glu-Asn-Arg is adjusted to pH=pl. The solution is then titrated with 0.2M HCI to a final pH of 2.1. Sketch the titration curve, labelling the pH and volume axes. Indicate the volume of HCl needed to reach each relevant pKa value and equivalence point(s). Relevant pka values are: 2.1, 4.3, 6.0, 8.3, 9.8, and 12.5.The skeletal structures of the two amino acids, glycine and lysine, are given below along with the values of the relevant acid dissociation constants (pKa). NH,* PK, - 10.79 - HạN*CH2CO,¯ S pK¸=2.35 (CH2)4 - H3N*CHCO,- pK,=9,78 lysine (Lys) glycine (Gly) pK, = 9.18 pK, - 2.16 For an aqueous solution of glycine alone, calculate the value of pH at which the ratio of the concentration of neutral glycine zwitterions to the concentration of protonated cation is 102. On your under each of the following conditions. In the blank, provide the total charge of the dipeptide. (Example: If the charge is two plus write the answer simply as 2, if the charge is negative two write the answer as -2). draw the skeletal structure of the dipeptide, Lys-Gly, when it is solvated in an aque us solution i. pH= 1 ii. pH= 12Draw dipeptide Arg-Thr at pH 6.0. Circle the six atoms that are restricted in one plane. Calculate its approximate pI assuming pKa for NH3+ is 10.0, pKa for COOH is 3.0, PKR for Arg is 12.0
- The main constituents in vinegar are water and ethanoic acid (CH3COOH). In order to determine the concentration of acid in homemade vinegar, a student titrated 25 cm3 of 001 M NaOH against the vinegar. The equation for the reaction is: CH3COOH(aq) + NaOH(aq) ® CH3COONa(aq) + H2O(l) The following titration results were obtained: Burette readings (cm3) Rough 1 2 Final burette reading 20.10 38.90 31.40 Initial burette reading 0.10 20.00 12.50 Volume of vinegar used 20.00 18.90 18.90 (a) What volume of vinegar should be used in the calculation? (b) What is the mole ratio of NaOH:CH3COOH? (c) Calculate the number of moles of alkali in 25 cm3 of NaOH solution used. (d) How many moles of acid were used in the titration? (e) Calculate the…A monoprotic weak acid, HA, dissociates in water according to the reaction HA(aq) = H*(aq) + A¯(aq) The equilibrium concentrations of the reactants and products are [HA] = 0.290 M, H+| = 3.00 × 10¬4 M, and [A-] = 3.00 x 10-4 M. Calculate the value of pKa for the acid HA. pKa3. Compute for the amount of each component of KCN broth if you were to prepare 280 ml. Express your answers using two decimal places. Follow this format in typing your answers: answerabbreviated unit (e.g. 3.00 g, 0.75 ml, 10.25 mg): Components Amount per liter Polypeptone 3.0 g NazHPO4 5.64 g (Available as NazHPO4 · 7H2O*) Monopotassium phosphate 0.225 g Sodium chloride 0.5% KCN 0.075 g (Available as 10,000 ppm solution) *MW (g/mol): Na-23; P-31; H-1; O-16 3.4. Sodium chloride (
- 3. Compute for the amount of each component of KCN broth if you were to prepare 280 ml. Express your answers using two decimal places. Follow this format in typing your answers: answerabbreviated unit (e.g. 3.00 g, 0.75 ml, 10.25 mg): Components Amount per liter Polypeptone 3.0 g NazHPO4 5.64 g (Available as NazHPO4 · 7H2O*) Monopotassium phosphate 0.225 g Sodium chloride 0.5% KCN 0.075 g (Available as 10,000 ppm solution) *MW (g/mol): Na-23; P-31; H-1; 0-16 3.5. KCN ("3. Compute for the amount of each component of KCN broth if you were to prepare 280 ml. Express your answers using two decimal places. Follow this format in typing your answers: answerabbreviated unit (e.g. 3.00 g, 0.75 ml, 10.25 mg): Components Amount per liter Polypeptone 3.0 g NazHPO4 5.64 g (Available as NazHPO4 · 7H2O*) Monopotassium phosphate 0.225 g Sodium chloride 0.5% KCN 0.075 g (Available as 10,000 ppm solution) *MW (g/mol): Na-23; P-31; H-1; 0-16 3.2. Na2HPO4 • 7H2O!'For the following concentrations, determine the equivalent of a. 75ug/mg lyophilized protein in ppm b. 6.3 x 10° mg/L of glycogen in % (w/v)