Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN: 9780134463216
Author: Robert F. Blitzer
Publisher: PEARSON
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**Problem:**

Jason went outside to take the temperature twice during the day. If the temperature at 11:00 am was \( -4^\circ \) and the temperature at 4:00 pm was \( 16^\circ \), what was the difference in temperature from 11:00 am to 4:00 pm?

**Solution Explanation:**

To find the difference in temperature, subtract the initial temperature from the final temperature:

1. Initial temperature at 11:00 am: \( -4^\circ \)
2. Final temperature at 4:00 pm: \( 16^\circ \)

The difference in temperature is calculated as:

\[ 
16^\circ - (-4^\circ) = 16^\circ + 4^\circ = 20^\circ 
\]

Thus, the temperature increased by \( 20^\circ \) from 11:00 am to 4:00 pm.
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Transcribed Image Text:**Problem:** Jason went outside to take the temperature twice during the day. If the temperature at 11:00 am was \( -4^\circ \) and the temperature at 4:00 pm was \( 16^\circ \), what was the difference in temperature from 11:00 am to 4:00 pm? **Solution Explanation:** To find the difference in temperature, subtract the initial temperature from the final temperature: 1. Initial temperature at 11:00 am: \( -4^\circ \) 2. Final temperature at 4:00 pm: \( 16^\circ \) The difference in temperature is calculated as: \[ 16^\circ - (-4^\circ) = 16^\circ + 4^\circ = 20^\circ \] Thus, the temperature increased by \( 20^\circ \) from 11:00 am to 4:00 pm.
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