10) Hg. Find the volume of the nitrogen when its pressure is changed to 0.526 atm while the temperature is held constant. A tank of nitrogen has a volume of 10.0 L and a pressure of 760.0 mm a) 1L c) 14,449L d) 0.0526 L b) 19L

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### Physics Problems: Gas Laws

#### Problem 10
**Question:**
A tank of nitrogen has a volume of 10.0 L and a pressure of 760.0 mm Hg. Find the volume of the nitrogen when its pressure is changed to 0.526 atm while the temperature is held constant.

**Options:**
a) 1 L  
b) 19 L  
c) 14,449 L  
d) 0.0526 L  

#### Problem 11
**Question:**
How many moles of \( \text{O}_2 \) would occupy 5 L at \( 25^\text{0} \text{Celsius} \) and 1.5 atm?

**Additional Information:**
- There are no graphs or diagrams provided in this image.

These problems are designed to test your understanding of the Gas Laws in Physics, specifically Boyle's Law and the Ideal Gas Law.

---

### Explanation

**Problem 10:**
In this question, Boyle's Law can be applied, which states that for a given mass of gas at constant temperature, the product of the pressure and volume is constant. Mathematically, it is expressed as:
\[ P_1 V_1 = P_2 V_2 \]
Where:
- \( P_1 \) and \( V_1 \) are the initial pressure and volume.
- \( P_2 \) and \( V_2 \) are the final pressure and volume.

Given:
- \( P_1 = 760.0 \text{ mm Hg} \)
- \( V_1 = 10.0 \text{ L} \)
- \( P_2 = 0.526 \text{ atm} \)

Note that 760 mm Hg = 1 atm, so:
\[ P_1 = 1 \text{ atm} \]

Rewrite the equation:
\[ 1 \text{ atm} \times 10.0 \text{ L} = 0.526 \text{ atm} \times V_2 \]
\[ 10.0 = 0.526 \times V_2 \]
\[ V_2 = \frac{10.0}{0.526} \approx 19 \text{ L} \]

So, the correct answer is b) 19 L.

**Problem 11:**
For this question, the Ideal Gas Law is used, which is
Transcribed Image Text:### Physics Problems: Gas Laws #### Problem 10 **Question:** A tank of nitrogen has a volume of 10.0 L and a pressure of 760.0 mm Hg. Find the volume of the nitrogen when its pressure is changed to 0.526 atm while the temperature is held constant. **Options:** a) 1 L b) 19 L c) 14,449 L d) 0.0526 L #### Problem 11 **Question:** How many moles of \( \text{O}_2 \) would occupy 5 L at \( 25^\text{0} \text{Celsius} \) and 1.5 atm? **Additional Information:** - There are no graphs or diagrams provided in this image. These problems are designed to test your understanding of the Gas Laws in Physics, specifically Boyle's Law and the Ideal Gas Law. --- ### Explanation **Problem 10:** In this question, Boyle's Law can be applied, which states that for a given mass of gas at constant temperature, the product of the pressure and volume is constant. Mathematically, it is expressed as: \[ P_1 V_1 = P_2 V_2 \] Where: - \( P_1 \) and \( V_1 \) are the initial pressure and volume. - \( P_2 \) and \( V_2 \) are the final pressure and volume. Given: - \( P_1 = 760.0 \text{ mm Hg} \) - \( V_1 = 10.0 \text{ L} \) - \( P_2 = 0.526 \text{ atm} \) Note that 760 mm Hg = 1 atm, so: \[ P_1 = 1 \text{ atm} \] Rewrite the equation: \[ 1 \text{ atm} \times 10.0 \text{ L} = 0.526 \text{ atm} \times V_2 \] \[ 10.0 = 0.526 \times V_2 \] \[ V_2 = \frac{10.0}{0.526} \approx 19 \text{ L} \] So, the correct answer is b) 19 L. **Problem 11:** For this question, the Ideal Gas Law is used, which is
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