10-3 W). A laser pointer with a wavelength λ = 550 nm has an output power of 5.80 mW (1 mW = What is the laser pointer's output in photons per second? Recall that Planck's constant is h = 6.63 x 10-34 Js. n H sec ond To use scientific (exponential) notation for your answer, express it using "E". For example, 1.23 x 1014 is entered as 1.23E14.

10-3 W). A laser pointer with a wavelength λ = 550 nm has an output power of 5.80 mW (1 mW = What is the laser pointer's output in photons per second? Recall that Planck's constant is h = 6.63 x 10-34 Js. n H sec ond To use scientific (exponential) notation for your answer, express it using "E". For example, 1.23 x 1014 is entered as 1.23E14.

Stars and Galaxies (MindTap Course List)

10th Edition

ISBN:9781337399944

Author:Michael A. Seeds

Publisher:Michael A. Seeds

Chapter7: Atoms And Spectra

Section: Chapter Questions

Problem 9P

See similar textbooks

Similar questions

A photon has an energy of 1.9 meV (milli electron Volt). What is the wavelength of this photon, expressed in micrometers? Keep four significant digits. And the answer is NOT 6.543
5.2 A magnetic field of 1.5 Tesla was passed through a nucleus of a hydrogen atom, ¹H. Also a x- ray photon (f = 2 x 1019 Hz) was passed through the same atom. Hint: Planck's constant h = 6.626 x 10-34 Js (i) Compute the energy of a 2 x 1019 Hz x-ray photon? (ii) Calculate the energy of the photon that will be absorbed by a ¹H nucleus in a 1.5 Tesla magnetic field? (iii) Stipulate how the two energies compare, Ex/EH? 10 2 S Reset br ?,
What will be the energy associated with a blue photon (in electronvolts, eV), if the frequency of the blue light is 650 THz (Terahertz (THz); 1 Tera = 1012)? [Hint: Use Planck's equation: E - hf to calculate the photon energy! h- Planck's constant – 6.63 x 10-34 Js = 4.14 x1015 eVs] A. 6.5 eV B. 6.5×10-3 eV C. 2.7 eV D. 2.7×10-27eV E. 2.7x107 eV
a) What is the wavelength lambda (m) of green light having a frequency of 5.7 x 10^14 Hz. b). Determine the energy (J) of each photon of the green light using the formula E = hf, where E is energy in Joules, h is Planck's constant (6.62 x 10^-34 J/s) and f is frequency in Hz.
The wavelength of a certain laser is 0.66 microns, where 1 micron = 1 ⋅ 10-6 m.What is this wavelength in nanometers? (1 nm = 10-9m)? Please explain how you get th 6.6 x 10^2 First, explain in simple terms the power of ten, right or left. If you move the decimal point to the right it means a negative power. If you move the decimal point to left it is positive.
Find the energy of the following. Express your answers in units of electron volts, noting that 1 eV = 1.60 x 10-19 J. (a) a photon having a frequency of 6.50 x 10¹7 Hz (b) a photon having a wavelength of 2.50 x 10² nm Step 1 (a) The energy of a photon is given by E = hf, where h = 6.63 x 10-34 Js is Planck's constant and f the frequency of the electromagnetic wave associated with the photon. A photon having frequency f = 6.50 x 10¹7 Hz has an energy, expressed in units of electron volts, of E = hf = (6.63 × 10-34 J. s) (1 x 10³ ev. x 10¹7 Hz) 1 eV x 10-19 1
Calculate the wavelength of a photon that has energy 2.83 × 10−19 Joules. Give your answer in units of nano metres. Hint: Planck’s constant h = 6.625 × 10−34 J s.
A photon has an energy of 1.9 meV (milli electron Volt). What is the wavelength of this photon, expressed in micrometers? Keep four significant digits.
Most remote controllers for AV equipment emit radiation with the wavelength profile shown in the figure below. What is the energy of a photon that has a wavelength corresponding to the peak in the figure?Planck's constant is h = 6.626 ×× 10–34 J • s, and the speed of light is c = 3.00 × 108 m/s. Answer in KJ
3. The equation 1.45 in our textbook says that the de Broglie wavelength as a function of temperature is given by 1 Assuming the accepted accuracy for h, R, and m are very high, what is the V3MRT maximum uncertainty in the de Broglie wavelength if AT is the uncertainty in temperature?
A photon has an energy of 1.9 meV (milli electron Volt). What is the wavelength of this photon, expressed in micrometers? Keep four significant digits. Would I still use the formula E=hf or do I need to go a different route?
Quantum Dot: Patent number 60-985-841 is for a quantum dot that only emits and absorbs three wavelengths of light. The quantum dot is engineered to have three different electron energy levels: E₁=0.60 eV, E₂ = 2.53 eV, and E3 = 4.15 eV. The quantum dot contains a electron. single What is the minimum wavelength of light will this quantum dot will absorb and emit? Report your result in nanometers (nm).