Homework Help is Here – Start Your Trial Now!
Math
Advanced Math
-10-2 020 A= 26) Find etA, 3041. 11 = A= [] find etA. A₁ = -1, multiplicity of 2, A3=1. X=-1: Av=-Av -x+y+22= -x 1 Y=0 -y+42=-y-y=-y 2=-2,2=0 V₁ = (ó). Since only 1 eigenvector on d- multiplicity 2, A is not diagonalizable. Find V2: (A+IPV=0 0121/012/X 004 004 049 = 002/1002112, Let V₂ = (?). Find V3: =1, Av=AV 008 004 = 0. -x+y+22=x, 22=2x-y -Y+42=4, 22=y L& V3 = (3). 2=2. 102 P-1=/09: P-1 101-2 Then P= (P= (27). 10011. 2011, S = P(-2-10/P-1 S = 1/2-14 N = A-S = / 01-3 000 etAt(S+N) -ets, etN = to = ets.etN = P(0² = + 0) P₁1 [I+ + N + 1 ² N²] 012 et/ 1102 let 0,0 10-217-2 。 eto 01-20 001/o o etoo 1/100 e • 2et t 2et 0 et 11 t = 21-21 0 1 a -2 00 1 0 et tēt ēt (-24-2) + 2et et = PtA t tet 20+ + 2et 0 et

-10-2 020 A= 26) Find etA, 3041. 11 = A= [] find etA. A₁ = -1, multiplicity of 2, A3=1. X=-1: Av=-Av -x+y+22= -x 1 Y=0 -y+42=-y-y=-y 2=-2,2=0 V₁ = (ó). Since only 1 eigenvector on d- multiplicity 2, A is not diagonalizable. Find V2: (A+IPV=0 0121/012/X 004 004 049 = 002/1002112, Let V₂ = (?). Find V3: =1, Av=AV 008 004 = 0. -x+y+22=x, 22=2x-y -Y+42=4, 22=y L& V3 = (3). 2=2. 102 P-1=/09: P-1 101-2 Then P= (P= (27). 10011. 2011, S = P(-2-10/P-1 S = 1/2-14 N = A-S = / 01-3 000 etAt(S+N) -ets, etN = to = ets.etN = P(0² = + 0) P₁1 [I+ + N + 1 ² N²] 012 et/ 1102 let 0,0 10-217-2 。 eto 01-20 001/o o etoo 1/100 e • 2et t 2et 0 et 11 t = 21-21 0 1 a -2 00 1 0 et tēt ēt (-24-2) + 2et et = PtA t tet 20+ + 2et 0 et

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 44RE
See similar textbooks
Question

Could you solve the problem completely using linear algebra handwritten?

-10-2 020 A= 26) Find etA, 3041.
Transcribed Image Text:-10-2 020 A= 26) Find etA, 3041.
11 = A= [] find etA. A₁ = -1, multiplicity of 2, A3=1. X=-1: Av=-Av -x+y+22= -x 1 Y=0 -y+42=-y-y=-y 2=-2,2=0 V₁ = (ó). Since only 1 eigenvector on d- multiplicity 2, A is not diagonalizable. Find V2: (A+IPV=0 0121/012/X 004 004 049 = 002/1002112, Let V₂ = (?). Find V3: =1, Av=AV 008 004 = 0. -x+y+22=x, 22=2x-y -Y+42=4, 22=y L& V3 = (3). 2=2. 102 P-1=/09: P-1 101-2 Then P= (P= (27). 10011. 2011, S = P(-2-10/P-1 S = 1/2-14 N = A-S = / 01-3 000 etAt(S+N) -ets, etN = to = ets.etN = P(0² = + 0) P₁1 [I+ + N + 1 ² N²] 012 et/ 1102 let 0,0 10-217-2 。 eto 01-20 001/o o etoo 1/100 e • 2et t 2et 0 et 11 t = 21-21 0 1 a -2 00 1 0 et tēt ēt (-24-2) + 2et et = PtA t tet 20+ + 2et 0 et
Transcribed Image Text:11 = A= [] find etA. A₁ = -1, multiplicity of 2, A3=1. X=-1: Av=-Av -x+y+22= -x 1 Y=0 -y+42=-y-y=-y 2=-2,2=0 V₁ = (ó). Since only 1 eigenvector on d- multiplicity 2, A is not diagonalizable. Find V2: (A+IPV=0 0121/012/X 004 004 049 = 002/1002112, Let V₂ = (?). Find V3: =1, Av=AV 008 004 = 0. -x+y+22=x, 22=2x-y -Y+42=4, 22=y L& V3 = (3). 2=2. 102 P-1=/09: P-1 101-2 Then P= (P= (27). 10011. 2011, S = P(-2-10/P-1 S = 1/2-14 N = A-S = / 01-3 000 etAt(S+N) -ets, etN = to = ets.etN = P(0² = + 0) P₁1 [I+ + N + 1 ² N²] 012 et/ 1102 let 0,0 10-217-2 。 eto 01-20 001/o o etoo 1/100 e • 2et t 2et 0 et 11 t = 21-21 0 1 a -2 00 1 0 et tēt ēt (-24-2) + 2et et = PtA t tet 20+ + 2et 0 et
Expert Solution
steps

Step by step

Solved in 2 steps with 4 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer