1.4 Calculate the reacting masses as given in the questions. (a) In the reaction below, 42.5g of ZnCl2 was formed. The relative formula masses are given as: ZnCl2 = 136.4 and FeCl2 = 126.6 ZnO + FeCl2 → ZnClz + FeO (i) Calculate the number of moles of ZNCI2 in 42.5g Answer: mol (ii) Calculate the number of moles of FeCl2 needed in the reaction. Answer:............. mol (iii) Calculate the mass of FeCl2 needed in the reaction. Answer: ......

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Calculate the reacting masses as given in the questions.
1.4 Calculate the reacting masses as given in the questions.
(a) In the reaction below, 42.5g of ZnCl2 was formed. The relative formula masses are given
as: ZnCl2 = 136.4 and FeCl, = 126.6
ZnO + FECI2 → ZnCl2 + FeO
(i)
Calculate the number of moles of ZnCl2 in 42.5g
Answer:
mol
(ii)
Calculate the number of moles of FeCl2 needed in the reaction.
Answer:
mol
(iii)
Calculate the mass of FeCl2 needed in the reaction.
Answer: ............
g
Transcribed Image Text:1.4 Calculate the reacting masses as given in the questions. (a) In the reaction below, 42.5g of ZnCl2 was formed. The relative formula masses are given as: ZnCl2 = 136.4 and FeCl, = 126.6 ZnO + FECI2 → ZnCl2 + FeO (i) Calculate the number of moles of ZnCl2 in 42.5g Answer: mol (ii) Calculate the number of moles of FeCl2 needed in the reaction. Answer: mol (iii) Calculate the mass of FeCl2 needed in the reaction. Answer: ............ g
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